如何识别特定视图中的触摸

Question

如何接触特定视图。

我正在使用

CGPoint Location = [[touches anyObject] locationInView:self.view ];

，但只想在单击特定子视图时触发该操作。
如何做到这一点。

Answer 1

我自己得到了答案......但感谢其他人在这方面帮助我，

这是

UITouch *touch ;
touch = [[event allTouches] anyObject];


    if ([touch view] == necessarySubView)
{
//Do what ever you want
}

Answer 2

试试这个

//here enable the touch
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    // get touch event
    UITouch *touch = [[event allTouches] anyObject];
    CGPoint touchLocation = [touch locationInView:self.view];

    if (CGRectContainsPoint(yoursubview_Name.frame, touchLocation)) {
        //Your logic
        NSLog(@" touched");
    }
}

Answer 3

您应该创建 UIView 的子类（或创建类别）并覆盖

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event

将消息重定向到适当的委托的位置。

Answer 4

// here Tiles is a separate class inherited from UIView Class
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    UITouch *touch = [touches anyObject];
    if ([[touch view] isKindOfClass:[Tiles class]]) {
        NSLog(@"[touch view].tag = %d", [touch view].tag);
    }
}

像这样你可以发现视图或子视图被触摸

Answer 5

这是一个不带多点触控的 swift3 版本：

override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
    if let touch = touches.first, self.bounds.contains(touch.location(in: self)) {
        // Your code
    }
}

Answer 6

你尝试过吗

CGPoint Location = [[touches anyObject] locationInView:necessarySubView ];