Python 解决“Goto”问题

发布于 2024-10-20 09:28:22 字数 330 浏览 8 评论 0原文

目前我要检查字符串中是否包含特定字符。

我正在尝试寻找“Goto”功能的解决方法。

这就是我现在所拥有的：

chars = set('0123456789$,')

if any((c in chars) for c in UserInputAmount):
    print 'Input accepted'
else:
    print 'Invalid entry. Please try again'

如果条目无效，我只需要 Python 返回到“UserInputAmount”的字符串输入。如果能朝正确的方向推动，我们将不胜感激。

原文

At the moment I have a check to see if a string has specific characters in it.

I am trying to find a work around for a 'Goto' function.

This is what I have at the moment:

chars = set('0123456789$,')

if any((c in chars) for c in UserInputAmount):
    print 'Input accepted'
else:
    print 'Invalid entry. Please try again'

I just need Python to go back to the string input of 'UserInputAmount' if the entry is invalid. A push in the right direction would be appreciate.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

一影成城 2024-10-27 09:28:22

你不需要 goto，你只需要一个循环。试试这个，除非用户提供有效的输入，否则它将永远循环：

chars = set('0123456789$,')

while True: # loop "forever"
    UserInputAmount = raw_input() # get input from user

    if any((c in chars) for c in UserInputAmount):
        print 'Input accepted'
        break # exit loop

    else:
        print 'Invalid entry. Please try again'
        # input wasn't valid, go 'round the loop again

You don't need a goto, you just need a loop. Try this, which loops forever unless the user provides valid input:

chars = set('0123456789$,')

while True: # loop "forever"
    UserInputAmount = raw_input() # get input from user

    if any((c in chars) for c in UserInputAmount):
        print 'Input accepted'
        break # exit loop

    else:
        print 'Invalid entry. Please try again'
        # input wasn't valid, go 'round the loop again

回复收藏 0 原文

如梦 2024-10-27 09:28:22

当我学习 Pascal 时，我们使用了一种称为“启动阅读”的小技巧：

chars = set('0123456789$,')

UserInputAmount = raw_input("Enter something: ")
while not any((c in chars) for c in UserInputAmount):
    UserInputAmount = raw_input("Wrong! Enter something else: ")
print "Input accepted."

A little technique we used to call a "priming read" back when I learned Pascal:

chars = set('0123456789$,')

UserInputAmount = raw_input("Enter something: ")
while not any((c in chars) for c in UserInputAmount):
    UserInputAmount = raw_input("Wrong! Enter something else: ")
print "Input accepted."

回复收藏 0 原文

深海里的那抹蓝 2024-10-27 09:28:22

重复本的：


>>> chars = set('1234567')
>>> while not any((c in chars) for c in raw_input()):
...  print 'try again'
... else:
...  print 'accepted'
... 
abc
try again
123
accepted

riffing on Ben's:


>>> chars = set('1234567')
>>> while not any((c in chars) for c in raw_input()):
...  print 'try again'
... else:
...  print 'accepted'
... 
abc
try again
123
accepted

回复收藏 0 原文

套路撩心 2024-10-27 09:28:22

goodEntry = False
first = True
chars = frozenset("abc")  #whatever
validateEntry = lambda x: any( (c in chars) for c in inString)

while not goodEntry:
    if not first: print "Invalid input"
    first = False
    print "Enter input: "
    inString = raw_input()
    goodEntry = validateEntry(inString)

goodEntry = False
first = True
chars = frozenset("abc")  #whatever
validateEntry = lambda x: any( (c in chars) for c in inString)

while not goodEntry:
    if not first: print "Invalid input"
    first = False
    print "Enter input: "
    inString = raw_input()
    goodEntry = validateEntry(inString)

回复收藏 0 原文

~没有更多了~