>?= 运算符是什么意思？
查看这个 C++ BigInt 库并找到 BigInt.cpp 文件。顶部有一条关于兼容性的评论：
此类是为 g++ 编译器编写的，并使用一些 g++ 扩展（例如“long double”和“>?=”运算符）。
>?= 运算符的作用是什么？我在其他地方找不到对它的引用。
Looking through this C++ BigInt library and found the BigInt.cpp file. At the top there is a a comment at the top about compatibility:
This class was written for the g++ compiler and uses some of the g++ extensions (like "long double" and the ">?=" operator).
What does that >?= operator do? I can't find a reference to it anywhere else.
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它是一个 GCC 扩展，已在 GCC 4.2 版及更高版本中删除。
a >?= b的等价物是a = max(a,b);还有一个非常相似的运算符
a 与a = min(a, b);含义相同。It's a GCC extension that was removed in GCC version 4.2 and later.
The equivalent of
a >?= bisa = max(a,b);There is also a very similar operator
a <?= bwhich means the same asa = min(a, b);.此页面描述了
>?< /code> 是“最大值”运算符，它返回两个数字参数中最大的一个。我猜测>?=将其与赋值相结合，如果右侧值较大，则可能通过分配给左侧操作数。This page describes that
>?is the 'maximum' operator, which returns the largest of its two numeric arguments. I'm guessing that the>?=combines this with assignment, presumably by assigning to the left-hand operand if the right-hand value is larger.请参阅 C 扩展：？运算符
这是 max-then-assign 运算符：取左侧和右侧中较大的一个，并将其放回左侧。
它已从 g++ 中删除，应替换为
max（或minfor）See C extension: <? and >? operators
It's the max-then-assign operator: Take the greater of the left and right sides and stuff it back into the lefthand side.
It's removed from g++ and should be replaced with
max(orminfor<?=)