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在模型验证的 mvc 问题中返回 JavaScriptResult

发布于 2024-10-20 08:26:23 字数 131 浏览 1 评论 0原文

我有 JavaScriptResult 的 post 方法的返回类型。我想通过 return new JavaScriptResult(){} 对此方法进行模型验证。我该怎么做？就像如果存在模型级别错误我应该返回什么一样。

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↙厌世 2024-10-27 08:26:23

一般来说，我会尽量避免使用 JavaScriptResult，因为它往往会将 UI 内容与控制器内容混合在一起，这往往违背整个 MVC 模式。如果我正在做您想要完成的事情，我会将 JsonResult 返回给客户端，然后根据结果执行一段代码。这样，如果模型验证失败，您可以返回包含失败结果的 JsonResult 并在客户端上知道验证失败。它可以这样实现：

[HttpPost]
public JsonResult Example(ModelName model)
{
    // Validate 
    if (!ModelState.IsValid)
    {
        return new JsonResult()
        {
            Data = new { success = false },
            JsonRequestBehavior = JsonRequestBehavior.AllowGet
        };
    }

    // No validation errors, do stuff

    return new JsonResult()
    {
        Data = new { success = true },
        JsonRequestBehavior = JsonRequestBehavior.AllowGet
    };

}

然后客户端代码：

$.post('/Example', $('#form').serialize(), function (response) {
    if (response.success) {
        // Success, execute js code here
    } else {
        // Validation errors
    }
}, "json");

但是，如果您需要使用 JavaScriptResult 路由并且发生验证错误，我将不返回任何内容，或者返回一些 javascript 来通知用户验证失败：

[HttpPost]
public JavaScriptResult Example(ModelName model)
{
    // Validate 
    if (!ModelState.IsValid)
    {
        return new JavaScript("alert("Validation Failed!")");
    }

    // No validation errors, do stuff

    return new JavaScript("js to return here if validation passes");
}

Generally, I would try to avoid using JavaScriptResult as it tends to intermingle UI content with controller content, which tends to go against the whole MVC pattern. If I were doing what you were trying to accomplish I would return a JsonResult back to the client and then execute a block of code based on the result. This way if a model fails validation you could return a JsonResult with a failure result and know on the client that the validation failed. It can be achieved like this:

[HttpPost]
public JsonResult Example(ModelName model)
{
    // Validate 
    if (!ModelState.IsValid)
    {
        return new JsonResult()
        {
            Data = new { success = false },
            JsonRequestBehavior = JsonRequestBehavior.AllowGet
        };
    }

    // No validation errors, do stuff

    return new JsonResult()
    {
        Data = new { success = true },
        JsonRequestBehavior = JsonRequestBehavior.AllowGet
    };

}

Then client code:

$.post('/Example', $('#form').serialize(), function (response) {
    if (response.success) {
        // Success, execute js code here
    } else {
        // Validation errors
    }
}, "json");

However, if you need to go the JavaScriptResult route and a validation error occurs, I would either return nothing or some javascript that would notify the user that the validation failed:

[HttpPost]
public JavaScriptResult Example(ModelName model)
{
    // Validate 
    if (!ModelState.IsValid)
    {
        return new JavaScript("alert("Validation Failed!")");
    }

    // No validation errors, do stuff

    return new JavaScript("js to return here if validation passes");
}

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