iOS CoreMotion CMAttitude 相对于北极

Question

我目前正在使用 CoreMotion 的 DeviceMotion 来获取 iPhone 的方向（滚动、俯仰、偏航）。现在我想要相对于地理北极的这些值；因此，我需要一个包含滚动、俯仰和偏航值的 CMAttitude 参考对象，如果 iPhone 背面面向北极（3D），则会报告这些值。 CLLocationManager 仅返回 Tesla 中的磁航向 (x, y, z)。

您知道如何将这些值转换为横滚、俯仰和偏航吗？

预先感谢，

亚历山大

Answer 1

iOS 5提供了指定方法。在开发人员文档中查找 CMAttitudeReferenceFrameXTrueNorthZVertical。

Answer 2

伪代码：

1. 启动设备运动更新
2. 在后台启动相机预览；）
3. 从设备捕获当前重力读数作为 CMAcceleration...一旦您将重力存储在本地变量中。
4. 然后你必须获取 2 个向量并获取它们之间的角度，在本例中为 (0,0,-1) 的设备重力和真实的重力向量...
5. 然后我们将 theta 转换为 thetaPrime...一个变换与 CoreMotion 参考方向相匹配
6. 设置一个计时器来制作动画....
7. 在动画期间获取 MotionManager 的 deviceMotion 属性的旋转矩阵的倒数。
8. 以正确的顺序应用变换来反映设备当前的姿态（欧拉模式下的偏航、俯仰、滚动或设备四元数旋转......基本上有 3 种不同的方式来表达同一件事）

以下是代码：

- (void) initMotionCapture
{
    firstGravityReading = NO;
    referenceAttitude = nil;

    if (motionManager == nil)
    {
        self.motionManager = [CMMotionManager new];
    }
    motionManager.deviceMotionUpdateInterval = 0.01;
    self.gravityTimer = [NSTimer scheduledTimerWithTimeInterval:1/60.0 target:self selector:@selector(getFirstGravityReading) userInfo:nil repeats:YES];
}


- (void) getFirstGravityReading
{
    CMAcceleration currentGravity; 

    CMDeviceMotion *dm = motionManager.deviceMotion;
    referenceAttitude = dm.attitude;
    currentGravity = dm.gravity;

    [motionManager startDeviceMotionUpdates];

    if (currentGravity.x !=0 && currentGravity.y !=0 && currentGravity.z !=0)
    {
        NSLog(@"Gravity = (%f,%f,%f)", currentGravity.x, currentGravity.y, currentGravity.z);

        firstGravityReading = YES;
        [gravityTimer invalidate];
        self.gravityTimer = nil;
        [self setupCompass];
    }
}

- (void) setupCompass
{
    //Draw your cube... I am using a quartz 3D perspective hack!
    CATransform3D initialTransform = perspectiveTransformedLayer.sublayerTransform;
    initialTransform.m34 = 1.0/-10000;


    //HERE IS WHAT YOU GUYS NEED... the vector equations!
    NSLog(@"Gravity = (%f,%f,%f)", currentGravity.x, currentGravity.y, currentGravity.z);

    //we have current gravity vector and our device gravity vector of (0, 0, -1)
    // get the dot product
    float dotProduct = currentGravity.x*0 + currentGravity.y*0 + currentGravity.z*-1;
    float innerMagnitudeProduct = currentGravity.x*currentGravity.x + currentGravity.y + currentGravity.y + currentGravity.z*currentGravity.z;
    float magnitudeCurrentGravity = sqrt(innerMagnitudeProduct);
    float magnitudeDeviceVector = 1; //since (0,0,-1) computes to: 0*0 + 0*0 + -1*-1 = 1

    thetaOffset = acos(dotProduct/(magnitudeCurrentGravity*magnitudeDeviceVector));
    NSLog(@"theta(degrees) = %f", thetaOffset*180.0/M_PI);

    //Now we have the device angle to the gravity vector (0,0,-1)
    //We must transform these coordinates to match our 
    //device's attitude by transforming to theta prime
    float theta_deg = thetaOffset*180.0/M_PI;
    float thetaPrime_deg = -theta_deg + 90; // ThetaPrime = -Theta + 90 <==> y=mx+b

    NSLog(@"thetaPrime(degrees) = %f", thetaOffset*180.0/M_PI);

    deviceOffsetRotation = CATransform3DMakeRotation((thetaPrime_deg) * M_PI / 180.0, 1, 0, 0);
    initialTransform = CATransform3DConcat(deviceOffsetRotation, initialTransform);

    perspectiveTransformedLayer.sublayerTransform = initialTransform;

    self.animationTimer = [NSTimer scheduledTimerWithTimeInterval:1/60.0 target:self selector:@selector(tick) userInfo:nil repeats:YES];

}

- (void) tick
{
    CMRotationMatrix rotation;

    CMDeviceMotion *deviceMotion = motionManager.deviceMotion;
    CMAttitude *attitude = deviceMotion.attitude;

    if (referenceAttitude != nil)
    {
        [attitude multiplyByInverseOfAttitude:referenceAttitude];
    }
    rotation = attitude.rotationMatrix;

    CATransform3D rotationalTransform = perspectiveTransformedLayer.sublayerTransform;

    //inverse (or called the transpose) of the attitude.rotationalMatrix
    rotationalTransform.m11 = rotation.m11;
    rotationalTransform.m12 = rotation.m21;
    rotationalTransform.m13 = rotation.m31;

    rotationalTransform.m21 = rotation.m12;
    rotationalTransform.m22 = rotation.m22;
    rotationalTransform.m23 = rotation.m32;

    rotationalTransform.m31 = rotation.m13;
    rotationalTransform.m32 = rotation.m23;
    rotationalTransform.m33 = rotation.m33;

    rotationalTransform = CATransform3DConcat(deviceOffsetRotation, rotationalTransform);
    rotationalTransform = CATransform3DConcat(rotationalTransform, CATransform3DMakeScale(1.0, -1.0, 1.0));


    perspectiveTransformedLayer.sublayerTransform = rotationalTransform;
}

Answer 3

您需要时不时地将偏航值校准到磁航向，以确保您处于正确的轨道上。查看有关如何补偿指南针抖动的说明：补偿指南针iPhone 4 上的陀螺仪滞后

Answer 4

特斯拉值是磁场强度，是三个轴中每个轴感受到的磁“拉力”大小的度量。只有将这些信息与加速度计数据结合起来，并进行一系列奇特的数学运算，您才能获得实际的航向（设备相对于磁北“指向”的方向）。然后添加来自 GPS 的信息并进行更多数学计算，以获得真实航向（相对于地理北极）。

长话短说，您可能不想自己做数学计算。幸运的是，iOS 在其 CLHeading 对象中提供了MagneticHeading 和 trueHeading，可从 CLLocationManager 标题属性获取。

为了获得描述设备如何倾斜的俯仰和滚动，还需要对来自磁力计和加速度计的相同原始数据进行数学计算。抱歉，我不知道有任何用于俯仰和横滚的 iOS API。