按列值的前导字符对数据行进行分组

Question

我有一个如下所示的数组，我想要做的是根据 timestamp 列的日期子字符串创建多个子数组，例如 (2011-02-04)

Array
(
    [0] => Array
        (
            [avgvalue] => 0
            [maxvalue] => 0
            [minvalue] => 0
            [nrsamples] => 0
            [stddeviation] => 0
            [timestamp] => 2011-02-04T11:00:00.000Z
        )

    [1] => Array
        (
            [avgvalue] => 268.3
            [maxvalue] => 268.3
            [minvalue] => 268.3
            [nrsamples] => 0
            [stddeviation] => 0
            [timestamp] => 2011-02-04T12:00:00.000Z
        )

    [2] => Array
        (
            [avgvalue] => 268.391666667
            [maxvalue] => 268.4
            [minvalue] => 268.3
            [nrsamples] => 0.0288675134595
            [stddeviation] => 0.0288675134595
            [timestamp] => 2011-02-04T13:00:00.000Z
        )

    [3] => Array
        (
            [avgvalue] => 268.433333333
            [maxvalue] => 268.5
            [minvalue] => 268.4
            [nrsamples] => 0.0492365963918
            [stddeviation] => 0.0492365963918
            [timestamp] => 2011-02-04T14:00:00.000Z
        )

    [4] => Array
        (
            [avgvalue] => 268.5
            [maxvalue] => 268.5
            [minvalue] => 268.5
            [nrsamples] => 0
            [stddeviation] => 0
            [timestamp] => 2011-02-04T15:00:00.000Z
        )

    [5] => Array
        (
            [avgvalue] => 268.575
            [maxvalue] => 268.6
            [minvalue] => 268.5
            [nrsamples] => 0.0452267016867
            [stddeviation] => 0.0452267016867
            [timestamp] => 2011-02-04T16:00:00.000Z
        )

    [6] => Array
        (
            [avgvalue] => 268.616666667
            [maxvalue] => 268.7
            [minvalue] => 268.6
            [nrsamples] => 0.0389249472081
            [stddeviation] => 0.0389249472081
            [timestamp] => 2011-02-04T17:00:00.000Z
        )

    [7] => Array
        (
            [avgvalue] => 268.7
            [maxvalue] => 268.7
            [minvalue] => 268.7
            [nrsamples] => 0
            [stddeviation] => 0
            [timestamp] => 2011-02-04T18:00:00.000Z
        )

    [8] => Array
        (
            [avgvalue] => 268.741666667
            [maxvalue] => 268.8
            [minvalue] => 268.7
            [nrsamples] => 0.0514928650545
            [stddeviation] => 0.0514928650545
            [timestamp] => 2011-02-04T19:00:00.000Z
        )

    [9] => Array
        (
            [avgvalue] => 268.8
            [maxvalue] => 268.8
            [minvalue] => 268.8
            [nrsamples] => 0
            [stddeviation] => 0
            [timestamp] => 2011-02-04T20:00:00.000Z
        )

    [10] => Array
        (
            [avgvalue] => 268.883333333
            [maxvalue] => 268.9
            [minvalue] => 268.8
            [nrsamples] => 0.0389249472081
            [stddeviation] => 0.0389249472081
            [timestamp] => 2011-02-04T21:00:00.000Z
        )
 )

：上面的数组在每个子数组中都有一个时间戳键。我分解了时间戳值以将日期与时间分开，现在我无法将数组拆分为子数组。

我想要的是有一个 2011-02-04 数组（包含该日期的所有值）和另一个 2011-02-05 数组（包含所有那个日期）。这可以是动态的，我的意思是日期可以更多。那么，我该怎么做呢？

我希望它是：

array[0] => array(... list of all the values for 2011-02-04),
array[1] => array(...list of all values for 2011-02-05)

Answer 1

假设所有条目的日期格式都相同（看起来是这样），您可以简单地循环数组：

$result = array();

foreach($array as $item) {
    $date = strstr($item['timestamp'], 'T', true);
    if(!array_key_exists($date, $result)) {
        $result[$date] = array();
    }
    $result[$date][] = $item;
}

参考：strstr, array_key_exists

根据原始数组中项目的顺序，您可能必须使用 ksort 按时间顺序对 $result 数组进行排序。

Answer 2

在推送新子数组之前无需检查数组键是否存在。只需将子数组推入日期键控子数组即可。

解决方案很简单：(Demo)

$result = [];
foreach ($array as $row) {
    $result[substr($row['timestamp'], 0, 10)][] = $row;
}

分组后，如果要对组进行排序，请使用 ksort($result) 用于 ASC 或 krsort($result) 用于 DESC。如果您想重新索引第一级键，请使用$result = array_values($result)。