VB.net SendMessage等待问题

发布于 2024-10-20 02:33:16 字数 1709 浏览 5 评论 0原文

我使用以下代码单击一个按钮以显示另一个要单击的表单:

Dim hwnd As Integer = FindWindow(vbNullString, "Virtual CDRom Control Panel")
Dim x As Integer = FindWindowEx(hwnd, 0, vbNullString, "Driver Control ...")

SendMessage(x, BM_CLICK, 0&, 0&)
Thread.Sleep(200)
hwnd = FindWindow(vbNullString, "Virtual CD-ROM Driver Control")
Debug.Print(hwnd)

问题是,当它到达

SendMessage(x, BM_CLICK, 0&, 0&)

单击该按钮时,它在那里停止代码,直到我退出弹出的框。我希望能够继续而不必退出该框,因为下一行

hwnd = FindWindow(vbNullString, "Virtual CD-ROM Driver Control")

找到弹出窗口并单击按钮在那个盒子里面。

任何帮助都会很棒! :o)

大卫

已解决

Private Declare Function FindWindow Lib "user32.dll" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As IntPtr
Private Declare Function FindWindowEx Lib "user32.dll" Alias "FindWindowExA" (ByVal hWndParent As IntPtr, ByVal hWndChildAfter As Integer, ByVal lpClassName As String, ByVal lpWindowName As String) As IntPtr
Private Declare Function SendMessage Lib "user32.dll" Alias "SendMessageA" (ByVal hWnd As IntPtr, ByVal wMsg As Integer, ByVal wParam As Integer, ByVal lParam As IntPtr) As IntPtr
Private Declare Function PostMessage Lib "user32.dll" Alias "PostMessageA" (ByVal hwnd As IntPtr, ByVal wMsg As Integer, ByVal wParam As Integer, ByVal lParam As IntPtr) As IntPtr

Dim hwnd As IntPtr = FindWindow(vbNullString, "Virtual CDRom Control Panel")
Dim x As IntPtr = FindWindowEx(hwnd, 0, vbNullString, "Driver Control ...")

PostMessage(x, BM_CLICK, 0&, 0&)
Thread.Sleep(200)
hwnd = FindWindow(vbNullString, "Virtual CD-ROM Driver Control")
Debug.Print(hwnd)

I am using the following code to click a button for displaying another form to click on:

Dim hwnd As Integer = FindWindow(vbNullString, "Virtual CDRom Control Panel")
Dim x As Integer = FindWindowEx(hwnd, 0, vbNullString, "Driver Control ...")

SendMessage(x, BM_CLICK, 0&, 0&)
Thread.Sleep(200)
hwnd = FindWindow(vbNullString, "Virtual CD-ROM Driver Control")
Debug.Print(hwnd)

Problems is that when it gets to

SendMessage(x, BM_CLICK, 0&, 0&)

to click the button, it stops the code there until i exit out of the box that pops up. I want to be able to continue without having to exit the box since the next line

hwnd = FindWindow(vbNullString, "Virtual CD-ROM Driver Control")

finds the pop up window and will click on a button inside that box.

Any help would be great! :o)

David

SOLVED

Private Declare Function FindWindow Lib "user32.dll" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As IntPtr
Private Declare Function FindWindowEx Lib "user32.dll" Alias "FindWindowExA" (ByVal hWndParent As IntPtr, ByVal hWndChildAfter As Integer, ByVal lpClassName As String, ByVal lpWindowName As String) As IntPtr
Private Declare Function SendMessage Lib "user32.dll" Alias "SendMessageA" (ByVal hWnd As IntPtr, ByVal wMsg As Integer, ByVal wParam As Integer, ByVal lParam As IntPtr) As IntPtr
Private Declare Function PostMessage Lib "user32.dll" Alias "PostMessageA" (ByVal hwnd As IntPtr, ByVal wMsg As Integer, ByVal wParam As Integer, ByVal lParam As IntPtr) As IntPtr

Dim hwnd As IntPtr = FindWindow(vbNullString, "Virtual CDRom Control Panel")
Dim x As IntPtr = FindWindowEx(hwnd, 0, vbNullString, "Driver Control ...")

PostMessage(x, BM_CLICK, 0&, 0&)
Thread.Sleep(200)
hwnd = FindWindow(vbNullString, "Virtual CD-ROM Driver Control")
Debug.Print(hwnd)

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(1

永言不败 2024-10-27 02:33:16

尝试将 SendMessage 更改为 PostMessage

另请注意,所有 HWND 必须声明为 IntPtr
SendMessagePostMessagewParamlParam 也是 IntPtr
这将使您的代码与 x64 环境兼容。

Try changing SendMessage to PostMessage.

Also please note all HWNDs must be declared as IntPtr.
Also wParam and lParam for SendMessage and PostMessage are IntPtrs.
This will make you code compatible with x64 environment.

~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文