ActionScript - 使用 NumberFormatter 格式化零？

发布于 2024-10-19 20:53:11 字数 852 浏览 7 评论 0原文

我已将属性分配给 NumberFormatter 对象，以便格式化值包含前导零、尾随零和 2 位小数。

除非要格式化的数字为 0，否则格式化有效。我如何使用设置的属性格式化 0，以便 0 变为 0.00？

var numFormat:NumberFormatter = new NumberFormatter(LocaleID.DEFAULT);
numFormat.leadingZero = true;
numFormat.trailingZeros = true;
numFormat.fractionalDigits = 2;

trace(numFormat.formatNumber(46));      //46.00
trace(numFormat.formatNumber(0.556849));  //0.56
trace(numFormat.formatNumber(0));        //0

[编辑] 如果格式化的数字为 0，我已经通过手动附加区域小数分隔符和所需数量的小数位数来解决这个问题：

if (myFormattedNumber.text == "0" && numFormat.fractionalDigits)
   {
   myFormattedNumber.appendText(numFormat.decimalSeparator);

   for (var i:uint = 0; i < numFormat.fractionalDigits; i++)
       myFormattedNumber.appendText("0");
   }

我仍然很想知道这是一个错误还是一个功能，但这似乎是一个疏忽我。

原文

i've assigned properties to a NumberFormatter object so that formatted values contain a leading zero, trailing zeros and a 2 decimal places.

the formatting works unless the number being formatted is 0. how can i format a 0 with the set properties so that 0 becomes 0.00?

var numFormat:NumberFormatter = new NumberFormatter(LocaleID.DEFAULT);
numFormat.leadingZero = true;
numFormat.trailingZeros = true;
numFormat.fractionalDigits = 2;

trace(numFormat.formatNumber(46));      //46.00
trace(numFormat.formatNumber(0.556849));  //0.56
trace(numFormat.formatNumber(0));        //0

[EDIT]
i've remedied this problem by manually appending the locale decimal separator with the desired number of fractionalDigits if the formatted number is 0:

if (myFormattedNumber.text == "0" && numFormat.fractionalDigits)
   {
   myFormattedNumber.appendText(numFormat.decimalSeparator);

   for (var i:uint = 0; i < numFormat.fractionalDigits; i++)
       myFormattedNumber.appendText("0");
   }

i'm still very interested in knowing if this is a bug or a feature, but it seems like a oversight to me.

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爺獨霸怡葒院 2024-10-26 20:53:11

这并不性感，但这与我遇到类似问题时使用的类似：

function numberFormat(number:*, maxDecimals:int = 2, forceDecimals:Boolean = false, siStyle:Boolean = true):String 
{
    var i:int = 0, inc:Number = Math.pow(10, maxDecimals), str:String = String(Math.round(inc * Number(number))/inc);
    var hasSep:Boolean = str.indexOf(".") == -1, sep:int = hasSep ? str.length : str.indexOf(".");
    var ret:String = (hasSep && !forceDecimals ? "" : (siStyle ? "," : ".")) + str.substr(sep+1);
    if (forceDecimals) for (var j:int = 0; j <= maxDecimals - (str.length - (hasSep ? sep-1 : sep)); j++) ret += "0";
    while (i + 3 < (str.substr(0, 1) == "-" ? sep-1 : sep)) ret = (siStyle ? "." : ",") + str.substr(sep - (i += 3), 3) + ret;
    return str.substr(0, sep - i) + ret;
}


trace("zero: " + numberFormat(0, 2, true, false))

完整文章在这里

It's not sexy, but this was similar to what I used when I ran into a similar issue:

function numberFormat(number:*, maxDecimals:int = 2, forceDecimals:Boolean = false, siStyle:Boolean = true):String 
{
    var i:int = 0, inc:Number = Math.pow(10, maxDecimals), str:String = String(Math.round(inc * Number(number))/inc);
    var hasSep:Boolean = str.indexOf(".") == -1, sep:int = hasSep ? str.length : str.indexOf(".");
    var ret:String = (hasSep && !forceDecimals ? "" : (siStyle ? "," : ".")) + str.substr(sep+1);
    if (forceDecimals) for (var j:int = 0; j <= maxDecimals - (str.length - (hasSep ? sep-1 : sep)); j++) ret += "0";
    while (i + 3 < (str.substr(0, 1) == "-" ? sep-1 : sep)) ret = (siStyle ? "." : ",") + str.substr(sep - (i += 3), 3) + ret;
    return str.substr(0, sep - i) + ret;
}


trace("zero: " + numberFormat(0, 2, true, false))

Full article here

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