django 模板 forloop 可以重置吗？
是否可以将 forloop.counter 对象重置为零？
我用它来吐出对象，但是当对象类型发生变化时，我想将其归零，这样我就可以数到 5 个对象，并输出行尾对象（没有右填充）作为第五个也是唯一的第五个对象在那种类型中。
如果我有 5 个对象，前两个是 a 类型，接下来的 3 个是 b 类型，第五个总是会得到较小的填充，不用介意它只是线上的第三个。
这是我的模板代码：
{% for project in projects %}
{% ifchanged project.proj_type %}
{% forloop.counter=="1" %}
</div>
<div class="span-4 prepend-top">
<h5 class="right" >{{ project.proj_type }}</h5>
</div>
<div class="span-19 append-1 last" id="row-of-projects">
{% endifchanged %}
{% if forloop.counter|divisibleby:"4" %}
<div class="span-4 append-1 prepend-top last" id="project">
{% else %}
<div class="span-4 append-1 prepend-top" id="project">
{% endif %}
<p class="project-name">{{ project.name }}</p>
<a href="/gallery/{{ project.slug }}/" ><img src="/media/pa/photographs/{{ project.get_photograph }}-t.jpg" alt="{{ project.name }}" /></a>
</div id="project">
{% endfor %}
Is it possible to reset the forloop.counter object back to zero?
I'm using it to spit out objects, but when the object type changes I want to zero it, so that I can count to 5 objects and output an end of row object (with no right padding) as the fifth and only fifth object in that type.
And if I've got 5 objects, the first two are type a and the next 3 are type b, the fifth one will always get the smaller padding, never mind that its only the third on the line.
Here is my template code:
{% for project in projects %}
{% ifchanged project.proj_type %}
{% forloop.counter=="1" %}
</div>
<div class="span-4 prepend-top">
<h5 class="right" >{{ project.proj_type }}</h5>
</div>
<div class="span-19 append-1 last" id="row-of-projects">
{% endifchanged %}
{% if forloop.counter|divisibleby:"4" %}
<div class="span-4 append-1 prepend-top last" id="project">
{% else %}
<div class="span-4 append-1 prepend-top" id="project">
{% endif %}
<p class="project-name">{{ project.name }}</p>
<a href="/gallery/{{ project.slug }}/" ><img src="/media/pa/photographs/{{ project.get_photograph }}-t.jpg" alt="{{ project.name }}" /></a>
</div id="project">
{% endfor %}
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评论（2）
听起来你应该根据类型重新分组对象，并在内循环中进行填充。
It sounds like you should be regrouping objects based on type, and doing the padding in the inner loop.
我不太确定我是否理解您的需求。
您可以使用
regroup标签根据类型显示对象。您可以使用
class="{%cycle 'normal' 'normal' 'normal' 'normal' 'special' %}"为每五个元素设置不同的样式。I'm not quite sure that I understand what you need.
You can use the
regrouptag to display your objects according to type.And you can use
class="{% cycle 'normal' 'normal' 'normal' 'normal' 'special' %}"to style every fifth element differently.