实体框架 CTP5 代码优先映射 - 同一个表中的外键

发布于 2024-10-19 11:59:05 字数 482 浏览 6 评论 0原文

我如何使用模型构建器来映射这样的东西？其中有一个可为空的外键引用相同的表主键

Table: Task
taskID int pk
taskName varchar
parentTaskID int (nullable) FK

任务类：

public class Task
{
     public int taskID {get;set;}
     public string taskName {get;set;}
     public int parentTaskID {get;set;}
     public Task parentTask {get;set;}
}

...

    modelBuilder.Entity<Task>()
        .HasOptional(o => o.ParentTask)....

原文

How would I map something like this using the modelBuilder? Where theres a nullable foreign key referencing the same tables primary key

Table: Task
taskID int pk
taskName varchar
parentTaskID int (nullable) FK

Task class:

public class Task
{
     public int taskID {get;set;}
     public string taskName {get;set;}
     public int parentTaskID {get;set;}
     public Task parentTask {get;set;}
}

...

    modelBuilder.Entity<Task>()
        .HasOptional(o => o.ParentTask)....

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泪意 2024-10-26 11:59:05

以下代码为您提供了所需的架构。请注意，您还需要将 ParentTaskID 外键定义为可为空的整数，就像我在下面所做的那样。

public class Task
{
    public int TaskID { get; set; }
    public string TaskName { get; set; }        
    public int? ParentTaskID { get; set; }
    public Task ParentTask { get; set; }
}

public class Context : DbContext
{
    public DbSet<Task> Tasks { get; set; }

    protected override void OnModelCreating(ModelBuilder modelBuilder)
    {
        modelBuilder.Entity<Task>()
                    .HasOptional(t => t.ParentTask)
                    .WithMany()
                    .HasForeignKey(t => t.ParentTaskID);
    }
}

The following code gives you the desired schema. Note that you also need to define ParentTaskID foreign key as a nullable integer, like I did below.

public class Task
{
    public int TaskID { get; set; }
    public string TaskName { get; set; }        
    public int? ParentTaskID { get; set; }
    public Task ParentTask { get; set; }
}

public class Context : DbContext
{
    public DbSet<Task> Tasks { get; set; }

    protected override void OnModelCreating(ModelBuilder modelBuilder)
    {
        modelBuilder.Entity<Task>()
                    .HasOptional(t => t.ParentTask)
                    .WithMany()
                    .HasForeignKey(t => t.ParentTaskID);
    }
}

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