元胞数组语法
两个问题：
1）我发现一段代码，上面写着 cellArr{x}{y}{3,8} = 1.0;，我想知道 {3 ,8} 表示。该程序将连接图中的各个节点连接在一起。这里我们会说“在图 x 的集合中，图 y 从 3 到 8 的连接的顶点标签为 1.0”。不过，总的来说，语法 {3,8} 在 MatLab 中意味着什么？
2）这可能不是这个问题的地方，但如果我知道我总是会有顶点值，即小数/浮点数，我真的应该使用元胞数组吗？因为我知道我只会有一种数据类型，所以矩阵会更好吗？
谢谢 ：）。
Two questions:
1) I've found a piece of code that says something like cellArr{x}{y}{3,8} = 1.0;, I was wondering what the {3,8} means. The program connections various nodes in a collections of connected graphs together. Here we would say that "in the set of graphs x, the graph y's connection from 3 to 8 has a vertex label of 1.0". Still, in general what does the syntax {3,8} mean in MatLab?
2) This probably isn't the place for this question but should I really be using cell arrays if I know I'm always going to be having vertex values i.e. decimals/floats. Would a matrix be better because I know I'm only going to have a single data type?
Thank you :).
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元胞数组可以有多个维度，因此它们可以像其他索引一样使用多个下标进行索引 多维数组。语法
{3,8}正在索引一个（可能是）二维元胞数组，获取第三行第八列中的元胞内容。使用元胞数组有两个主要原因：存储不同类型的数据或存储不同大小的数据。假设示例中的 x 和 y 是标量索引，则 cellArr 是一个元胞数组，其中元胞由 x 索引> 包含另一个元胞数组，其由
y索引的元胞包含一个存储顶点标签的二维元胞数组。现在，如果您的顶点标签都是相同的数据类型并且都只是单个非空（即不是
[]）值，那么最低级别的二维元胞数组可以转换为二维数值数组，您的索引将如下所示：现在的问题是如何处理由
x和y索引的两组封闭元胞数组。如果可以通过 y 索引的每个单元格都包含大小和类型相同的二维数值数组，则该单元格数组可以转换为 3D 数值数组可以像这样索引的数组：最后，如果可以通过
x索引的每个单元格都包含同样大小和类型相同的 3-D 数值数组，则cellArr可以转换为 4-D 数值数组，可以像这样进行索引：您可以根据自己的喜好更改下标的顺序（即
numArr的尺寸），但我将x和y放在因此，如果您要索引顶点标签的子数组，例如 numArr(:,:,y,x) ，它将以二维数组的形式返回。如果您对索引进行了排序，以便对顶点标签的子数组进行索引，例如 numArr(x,y,:,:)，它将以 4 维数组的形式返回结果，其中包含两个主要的单例维度（您必须使用 SQUEEZE 等函数删除它们)。Cell arrays can have multiple dimensions, and thus they can be indexed with multiple subscripts like any other multidimensional array. The syntax
{3,8}is indexing a (presumably) 2-D cell array, getting the contents of the cell in the third row and eighth column.There are two main reasons to use cell arrays: storing data of different types or storing data of different sizes. Assuming
xandyare scalar indices in your example, thencellArris a cell array with the cell indexed byxcontaining another cell array, whose cell indexed byycontains a 2-D cell array which stores your vertex labels.Now, if your vertex labels are all the same data type and are all just single non-empty (i.e. not
[]) values, then the 2-D cell array at the lowest level could be turned into a 2-D numeric array, and your indexing will look like this:The question now becomes how to handle the two enclosing sets of cell arrays indexed by
xandy. If every cell that can be indexed byycontains 2-D numeric arrays all of the same size and type, then that cell array could be turned into a 3-D numeric array that could be indexed like so:Finally, if every cell that can be indexed by
xcontains 3-D numeric arrays that are again all of the same size and type, thencellArrcould be turned into a 4-D numeric array that could be indexed like so:You could change the order of the subscripts (i.e. the dimensions of
numArr) to your liking, but I putxandyat the end so that if you were to index a subarray of vertex labels likenumArr(:,:,y,x)it will return it as a 2-D array. If you had the indices ordered such that you would index a subarray of vertex labels likenumArr(x,y,:,:), it will return the result as a 4-D array with ones for the two leading singleton dimensions (which you would have to remove using functions like SQUEEZE).{3,8}是元胞数组索引，就像{x}和{y}一样。所以 cellArr 是细胞向量的细胞向量。这些单元向量之一由{x}索引。该元胞向量本身就是一个元胞二维矩阵向量，由{y}索引。最后，这个单元矩阵由{3,8}索引，即第3行第8列。numericArray[x, y, 3, 8]索引。{3,8}are cell array indices just as the{x}and{y}are. So cellArr is a cell vector of cell vectors. One of these cell vectors is indexed by{x}. This cell vector is itself a vector of cell 2d-matrices which is indexed by{y}. Finally, this cell matrix is indexed by{3,8}, i.e. the 3rd row and 8th column.numericArray[x, y, 3, 8].