当 XML 节点从列表序列化时，如何向该节点添加属性？

Question

我问了这个问题昨天，想知道如何使用 MVCContrib 生成带有属性的 XML。答案是使用[XmlAttribute]。

此后，我已成功使用 [XmlAttribute] 获取以下 XML：

<?xml version="1.0" encoding="utf-8"?>
<TopTen xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <SectorName>Property - Direct UK</SectorName>
  <PerformanceTo>2011-01-31T00:00:00</PerformanceTo>
  <OrderedShareClassReturns>
    <OrderedShareClassReturn Name="Property L" Performance="11.074980" />
    <OrderedShareClassReturn Name="UK Property Trust I Inc" Performance="10.512610" />
    <OrderedShareClassReturn Name="UK Property Trust I Acc" Performance="10.466310" />
    <OrderedShareClassReturn Name="UK Property Trust R Inc" Performance="9.725650" />
  </OrderedShareClassReturns>
</TopTen>

现在我需要向 XML 添加第二个 节点，并且我将喜欢向该元素添加属性，因此 XML 变为：

<?xml version="1.0" encoding="utf-8"?>
<TopTen xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <SectorName>Property - Direct UK</SectorName>
  <PerformanceTo>2011-01-31T00:00:00</PerformanceTo>
  <OrderedShareClassReturns order="top"> // how can I add the "top" & "bottom" attributes?
    <OrderedShareClassReturn Name="Property L" Performance="11.074980" />
    <OrderedShareClassReturn Name="UK Property Trust I Inc" Performance="10.512610" />
    <OrderedShareClassReturn Name="UK Property Trust I Acc" Performance="10.466310" />
    <OrderedShareClassReturn Name="UK Property Trust R Inc" Performance="9.725650" />
  </OrderedShareClassReturnss>
  <OrderedShareClassReturns order="bottom">
    <OrderedShareClassReturn Name="Property L" Performance="0.074980" />
    <OrderedShareClassReturn Name="UK Property Trust I Inc" Performance="1.512610" />
    <OrderedShareClassReturn Name="UK Property Trust I Acc" Performance="2.466310" />
    <OrderedShareClassReturn Name="UK Property Trust R Inc" Performance="3.725650" />
  </OrderedShareClassReturns>
</TopTen>

但我不知道该怎么做。我要序列化的对象定义为：

public class TopTen
{

    public string SectorName { get; set; }
    public DateTime PerformanceTo { get; set; }

    public List<OrderedShareClassReturn> OrderedShareClassReturns { get; set; }
}

public class OrderedShareClassReturn
{
    [XmlAttribute]
    public string Name { get; set; }

    [XmlAttribute]
    public decimal Performance { get; set; }
}

所以问题是，如何将该属性添加到 元素？我是否需要将 OrderedShareClassReturns 定义为实现 List 的类，并具有名为 order 的属性，该属性具有 [XmlAttribute]？或者有更简单的方法吗？

Answer 1

为此，您需要添加另一个类：

public class ReturnsWrapper {

    [XmlElement("OrderedShareClassReturn")]
    public List<OrderedShareClassReturn> Items { get; set; }

    [XmlAttribute("order")]
    public string Order {get;set;}
}

并具有：

public class TopTen
{

    public string SectorName { get; set; }
    public DateTime PerformanceTo { get; set; }
    [XmlElement("OrderedShareClassReturns")]
    public List<ReturnsWrapper> Returns { get; set; }
}