将图像文件插入 php 的 imagecreate

发布于 2024-10-19 05:39:50 字数 615 浏览 3 评论 0原文

我正在尝试动态生成一个由其他较小图像组成的图像文件。这是我到目前为止得到的代码

    if ( function_exists('imagecreate') ) {
        header ("Content-type: image/png");
        $im = @imagecreate ($imgWidth, $imgHeight)
            or die ("Cannot initialize new GD image stream");
        $background_color = imagecolorallocate ($im, 255, 255, 255);
        $text_color = imagecolorallocate ($im, 0,0,0);
        imagepng ($im);
        imagedestroy($im);
    }

，到目前为止，它运行良好。我只是不知道如何将较小的图像包含到这个新的、更大的、动态生成的图像中。有谁知道该怎么做？理想情况下，执行此操作（或无论它是什么）的函数会要求我提供图像文件，即第二个图像文件中的 x 和 y 位置。

有什么建议吗？我真诚地感谢您能给我带来的任何帮助。非常感谢你！！

原文

I'm trying to dynamically generate an image file that will be composed by other smaller images. This is the code I've got so far

    if ( function_exists('imagecreate') ) {
        header ("Content-type: image/png");
        $im = @imagecreate ($imgWidth, $imgHeight)
            or die ("Cannot initialize new GD image stream");
        $background_color = imagecolorallocate ($im, 255, 255, 255);
        $text_color = imagecolorallocate ($im, 0,0,0);
        imagepng ($im);
        imagedestroy($im);
    }

So far, it's working fine. I just can't figure out how to include my smaller images into this new, bigger, dynamically generated image. Does anyone know how to do this? Ideally, the function that does this (or whatever it is) would ask me for the image file, it's x and y positions in the second image file.

Any suggestions? I sincerely appreciate any help you can bring me. Thank you so so much!!

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