根据另一个矩阵中的排列构造矩阵
我有一个维度为（mxn）的矩阵“eff_tot”，我想根据名为“matches”的矩阵重新排列它（例如[n2 n3; n4 n5]）并将所有未指定的列放在末尾有“匹配”。
也就是说，我想要 [eff_tot(:,n2) eff_tot(:,n3) ； eff_tot(:,n4) eff_tot(:,n5) ; eff_tot(:,n1)]。
这就是大家！
以第一个答案中的例子为例，我想要的是：
eff_tot =
81 15 45 15 24
44 86 11 14 42
92 63 97 87 5
19 36 1 58 91
27 52 78 55 95
82 41 0 0 0
87 8 0 0 0
9 24 0 0 0
40 13 0 0 0
26 19 0 0 0
问候。
I have a matrix 'eff_tot' with dimension (m x n) which I want to rearrange according to a matrix called 'matches' (e.g. [n2 n3; n4 n5]) and put all the collumns not specified in 'matches' at the end.
That is, I want to have [eff_tot(:,n2) eff_tot(:,n3) ; eff_tot(:,n4) eff_tot(:,n5) ; eff_tot(:,n1)].
That's all folks!
Taking the example in the first answer, what I would like to have is:
eff_tot =
81 15 45 15 24
44 86 11 14 42
92 63 97 87 5
19 36 1 58 91
27 52 78 55 95
82 41 0 0 0
87 8 0 0 0
9 24 0 0 0
40 13 0 0 0
26 19 0 0 0
Regards.
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创建一个向量，列出
eff_tot中所有列的索引，然后使用 SETDIFF 确定哪些列不会出现在[n2 n3 n4 n5]中。这些列是无与伦比的。现在连接匹配和不匹配的列索引以创建列重新排序的eff_tot矩阵。>> eff_tot = randi(100, 5, 7) eff_tot = 45 82 81 15 15 41 24 11 87 44 14 86 8 42 97 9 92 87 63 24 5 1 40 19 58 36 13 91 78 26 27 55 52 19 95 >> n2 = 3; n3 = 5; n4 = 2; n5 = 6; >> missingColumn = setdiff(1:size(eff_tot, 2), [n2 n3 n4 n5]) missingColumn = 1 4 7 >> eff_tot = [eff_tot(:,n2) eff_tot(:,n3) eff_tot(:,missingIndex); eff_tot(:,n4) eff_tot(:,n5) zeros(size(eff_tot, 1), length(missingIndex))]; eff_tot = 81 15 45 15 24 44 86 11 14 42 92 63 97 87 5 19 36 1 58 91 27 52 78 55 95 82 41 0 0 0 87 8 0 0 0 9 24 0 0 0 40 13 0 0 0 26 19 0 0 0Create a vector listing the indices of all the columns in
eff_totand then use SETDIFF to determine which columns do not occur in[n2 n3 n4 n5]. These columns are the unmatched ones. Now concatenate the matched and unmatched column indices to create your column-reorderedeff_totmatrix.>> eff_tot = randi(100, 5, 7) eff_tot = 45 82 81 15 15 41 24 11 87 44 14 86 8 42 97 9 92 87 63 24 5 1 40 19 58 36 13 91 78 26 27 55 52 19 95 >> n2 = 3; n3 = 5; n4 = 2; n5 = 6; >> missingColumn = setdiff(1:size(eff_tot, 2), [n2 n3 n4 n5]) missingColumn = 1 4 7 >> eff_tot = [eff_tot(:,n2) eff_tot(:,n3) eff_tot(:,missingIndex); eff_tot(:,n4) eff_tot(:,n5) zeros(size(eff_tot, 1), length(missingIndex))]; eff_tot = 81 15 45 15 24 44 86 11 14 42 92 63 97 87 5 19 36 1 58 91 27 52 78 55 95 82 41 0 0 0 87 8 0 0 0 9 24 0 0 0 40 13 0 0 0 26 19 0 0 0