如何阻止来自 javascript 计时器的消息重复?
我的游戏有一个计时器,但该消息将继续在法师上显示,因此它会说多次,我想知道如何让它说一次。
<head>
<script type="text/javascript">
var c=10;
var t;
var timer_is_on=0;
function timedCount() {
document.getElementById('txt').value = c;
c = c - 1;
if (c == -1||c < -1){
var _message = document.createTextNode("You have mined 1 iron ore!");
document.getElementById('message').appendChild(_message);
startover();
}
}
function startover() {
c = 10;
clearTimeout(t);
timer_is_on=0;
doMining();
}
function doMining() {
if (!timer_is_on) {
timer_is_on = true;
t = setInterval(function () {
timedCount();
}, 1000);
}
}
</script>
<SPAN STYLE="float:left">
<form>
<input type="button" value="Mining" onClick="doMining()">
<input type="text" id="txt">
</form>
</SPAN>
<html>
<center>
<div id='message'></div>
I have a timer for my game, but the message will keep going on the mage, so it says it multiple times, i was wondering how you can get it to say it once.
<head>
<script type="text/javascript">
var c=10;
var t;
var timer_is_on=0;
function timedCount() {
document.getElementById('txt').value = c;
c = c - 1;
if (c == -1||c < -1){
var _message = document.createTextNode("You have mined 1 iron ore!");
document.getElementById('message').appendChild(_message);
startover();
}
}
function startover() {
c = 10;
clearTimeout(t);
timer_is_on=0;
doMining();
}
function doMining() {
if (!timer_is_on) {
timer_is_on = true;
t = setInterval(function () {
timedCount();
}, 1000);
}
}
</script>
<SPAN STYLE="float:left">
<form>
<input type="button" value="Mining" onClick="doMining()">
<input type="text" id="txt">
</form>
</SPAN>
<html>
<center>
<div id='message'></div>
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使用
window.setTimeout
而不是setInterval
。这只会触发该函数一次。
编辑:如果您希望每次显示并更新一条消息,请首先添加全局计数器:
然后将代码更改为:
这将分配元素的内容,而不是每次都添加到元素的内容。
Instead of
setInterval
usewindow.setTimeout
.This will trigger the function only once.
Edit: if you mean you want one message to appear and update every time, first add global counter:
Then change the code to this:
This will assign the contents of the element instead of adding to it each time.
您的
startOver
函数调用doMining()
。当然,不应该……?Your
startOver
function callsdoMining()
. Surely, it shouldn't...?