当我只有字符串格式的控件名称时，如何动态添加用户控件？银光，C#

发布于 2024-10-19 04:21:57 字数 462 浏览 2 评论 0原文

我正在努力调用不同的用户控件，并且给我的唯一数据是一个字符串，用于调用我创建的用户控件。当我知道名称时，我可以硬编码并在后面的代码中添加该控件，并以这种方式动态添加它，但是当控件的名称通过字符串传递给我时，我无法将其传递给我的usercontrol 对象并使其不为空...

这是我的代码：

string userControlName = "ReportFilterOptions";                
Type type = this.GetType();
Assembly assembly = type.Assembly;
UserControl c = (UserControl)assembly.CreateInstance(type.FullName + "." + userControlName);
gridReport.Children.Clear();
gridReport.Children.Add(c);

原文

I'm working on calling different user controls, and the only data that I've been given is a string in which to call the user control that I have created. When I know the name, I can hard code and add that control in the code behind and add it dynamically that way, but when the name of the control is being passed to me via a string, I'm having trouble passing that to my usercontrol object and having it not be null...

Here is my code:

string userControlName = "ReportFilterOptions";                
Type type = this.GetType();
Assembly assembly = type.Assembly;
UserControl c = (UserControl)assembly.CreateInstance(type.FullName + "." + userControlName);
gridReport.Children.Clear();
gridReport.Children.Add(c);

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琴流音 2024-10-26 04:21:57

使用System.Activator.CreateInstance。

请参阅此示例。重要的部分是：

// get type of class Calculator from just loaded assembly
Type calcType = testAssembly.GetType("Test.Calculator");

// create instance of class Calculator
object calcInstance = Activator.CreateInstance(calcType);

您可以通过迭代所有类型以匹配字符串来使其更加“用户友好”。

请参阅此文件的第 54 行左右< /a> 在方法 UpdateClassList 中。

Use System.Activator.CreateInstance.

See this example. The important parts are:

// get type of class Calculator from just loaded assembly
Type calcType = testAssembly.GetType("Test.Calculator");

// create instance of class Calculator
object calcInstance = Activator.CreateInstance(calcType);

You could make this more "user friendly" by iterating all the types to match string.

See around line 54 of this file in method UpdateClassList.

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