hibernate如何存储可嵌入的obj
有点愚蠢的问题，但我没有在任何地方找到答案。 @Embeddable 对象如何存储在数据库中，是一种与 FK 的 OneToOne 还是...例如，如果我有：
@Entity
public class User {
private Long id;
@Id
public Long getId() { return id; }
public void setId(Long id) { this.id = id; }
private Address address;
@Embedded
public Address getAddress() { return address; }
public void setAddress() { this.address = address; }
}
@Embeddable
public class Address {
private String street1;
public String getStreet1() { return street1; }
public void setStreet1() { this.street1 = street1; }
}
表应该是什么样子？
kind of stupid question but i didn't find the answer anywhere. How @Embeddable object is stored in the database, is it kind of OneToOne with FK or... For example if i have:
@Entity
public class User {
private Long id;
@Id
public Long getId() { return id; }
public void setId(Long id) { this.id = id; }
private Address address;
@Embedded
public Address getAddress() { return address; }
public void setAddress() { this.address = address; }
}
@Embeddable
public class Address {
private String street1;
public String getStreet1() { return street1; }
public void setStreet1() { this.street1 = street1; }
}
How the table(s) should look like?
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嵌入对象的字段作为列添加到所属实体的表中。
因此，您将拥有一个包含字段
id和street1的表User。The embedded object's fields are added as columns to the table of the owning Entity.
So you will have a table
Userwith fieldsidandstreet1.这非常简单：嵌入对象中的所有列都将合并到父对象的列中，从而形成一个表。在您的示例中，您最终将得到一个表
User，其中包含列：id和street1。因此，嵌入对象基本上是一种对一个表中的列进行逻辑分组的方法。It's very simple: all columns from the embedded object will be merged into columns of the parent, resulting with a single table. In your example you will end up with a table
Usercontaining columns:idandstreet1. So embedded objects are basically a way to logically group columns within one table.