如何在 RestSharp 中向请求正文添加文本

发布于 2024-10-19 01:37:06 字数 1040 浏览 3 评论 0原文

我正在尝试使用 RestSharp 来使用 Web 服务。到目前为止，一切进展顺利（为 John Sheehan 和所有贡献者干杯！），但我遇到了障碍。假设我想将 XML 以已序列化的形式（即作为字符串）插入到 RestRequest 的正文中。有没有简单的方法可以做到这一点？看来 .AddBody() 函数在幕后进行序列化，因此我的字符串被转换为。

非常感谢任何帮助！

编辑：请求提供我当前代码的示例。见下文 -

private T ExecuteRequest<T>(string resource,
                            RestSharp.Method httpMethod,
                            IEnumerable<Parameter> parameters = null,
                            string body = null) where T : new()
{
    RestClient client = new RestClient(this.BaseURL);
    RestRequest req = new RestRequest(resource, httpMethod);

    // Add all parameters (and body, if applicable) to the request
    req.AddParameter("api_key", this.APIKey);
    if (parameters != null)
    {
        foreach (Parameter p in parameters) req.AddParameter(p);
    }

    if (!string.IsNullOrEmpty(body)) req.AddBody(body); // <-- ISSUE HERE

    RestResponse<T> resp = client.Execute<T>(req);
    return resp.Data;
}

原文

I'm trying to use RestSharp to consume a web service. So far everything's gone very well (cheers to John Sheehan and all contributors!) but I've run into a snag. Say I want to insert XML into the body of my RestRequest in its already serialized form (i.e., as a string). Is there an easy way to do this? It appears the .AddBody() function conducts serialization behinds the scenes, so my string is being turned into <String />.

Any help is greatly appreciated!

EDIT: A sample of my current code was requested. See below --

private T ExecuteRequest<T>(string resource,
                            RestSharp.Method httpMethod,
                            IEnumerable<Parameter> parameters = null,
                            string body = null) where T : new()
{
    RestClient client = new RestClient(this.BaseURL);
    RestRequest req = new RestRequest(resource, httpMethod);

    // Add all parameters (and body, if applicable) to the request
    req.AddParameter("api_key", this.APIKey);
    if (parameters != null)
    {
        foreach (Parameter p in parameters) req.AddParameter(p);
    }

    if (!string.IsNullOrEmpty(body)) req.AddBody(body); // <-- ISSUE HERE

    RestResponse<T> resp = client.Execute<T>(req);
    return resp.Data;
}

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你好，陌生人 2024-10-26 01:37:06

以下是如何将纯 xml 字符串添加到请求正文中：

req.AddParameter("text/xml", body, ParameterType.RequestBody);

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信仰 2024-10-26 01:37:06

要添加到@dmitreyg的答案以及@jrahhali对其答案的评论，在当前版本中，截至发布时它是v105.2.3，语法如下：

request.Parameters.Add(new Parameter() { 
    ContentType = "application/json", 
    Name = "JSONPAYLOAD", // not required 
    Type = ParameterType.RequestBody, 
    Value = jsonBody
});

request.Parameters.Add(new Parameter() { 
    ContentType = "text/xml", 
    Name = "XMLPAYLOAD", // not required 
    Type = ParameterType.RequestBody, 
    Value = xmlBody
});

To Add to @dmitreyg's answer and per @jrahhali's comment to his answer, in the current version, as of the time this is posted it is v105.2.3, the syntax is as follows:

request.Parameters.Add(new Parameter() { 
    ContentType = "application/json", 
    Name = "JSONPAYLOAD", // not required 
    Type = ParameterType.RequestBody, 
    Value = jsonBody
});

request.Parameters.Add(new Parameter() { 
    ContentType = "text/xml", 
    Name = "XMLPAYLOAD", // not required 
    Type = ParameterType.RequestBody, 
    Value = xmlBody
});

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