使用 LINQ 查询 db4o 中的嵌套类?
db4o 和简单的嵌套结构遇到了一个棘手的问题。
问题:当我使用 LINQ 从 db4o 中提取数据时,它提取了太多数据(即“where”子句似乎不起作用)。
我有一些嵌套对象:
Root ----Symbol (SPX)
| |------Day 1: Date: 2010-10-18, string "SPX meta"
| |------Day 2: Date: 2010-10-19, string "SPX meta"
|
|
|-----Symbol (IBM)
|------Day 1: Date: 2010-10-18, string "IBM meta"
|------Day 2: Date: 2010-10-19, string "IBM meta"
我创建两个交易品种:
Symbol sym1 = new Symbol("SPX");
Symbol sym2 = new Symbol("IBM");
然后创建一些交易日:
// SPX
TradingDay day1 = new TradingDay(new DateTime(2010, 10, 18), "SPX meta");
TradingDay day2 = new TradingDay(new DateTime(2010, 10, 19), "SPX meta");
// IBM
TradingDay day3 = new TradingDay(new DateTime(2010, 10, 18), "IBM meta");
TradingDay day4 = new TradingDay(new DateTime(2010, 10, 19), "IBM meta");
然后为每个交易品种分配几天:
sym1.AssignTradingDay(day1);
sym1.AssignTradingDay(day2);
sym2.AssignTradingDay(day3);
sym2.AssignTradingDay(day4);
然后将其保存到 db4o 对象数据库:
// Store in the database.
db4o.db.Store(sym1);
db4o.db.Store(sym2);
db4o.db.Commit();
到目前为止非常简单。
我用“db4o Object Manager Enterprise”检查数据库,果然有两个符号,如果我单击每个符号,每个符号都包含两天。
现在,我执行 LINQ 查询来提取数据:
var daysForSymbolS1 = from Symbol s in db4o.db
from TradingDay t in db4o.db
where (s.SymbolGlobal == "IBM"
&& t.Date == new DateTime(2010, 10, 19))
select new
{
s.SymbolGlobal,
t.Date,
t.Meta
};
foreach (var d in daysForSymbolS1)
{
Console.WriteLine("{0} - {1} - {2}", d.SymbolGlobal, d.Date.Date, d.Meta);
}
而且,发生了一些奇怪的事情:
IBM - 10/19/2010 12:00:00 AM - SPX meta // This line should not appear because we have specified "IBM" in the filter.
IBM - 10/19/2010 12:00:00 AM - IBM meta
尽管我指定它应该只返回“SPX”的数据,但它也从“IBM”返回数据。
我做错了什么吗?
Run into a tricky problem with db4o and a simple nested structures.
Problem: when I use LINQ to pull data out of db4o, its pulling out too much data (i.e. the "where" clause doesn't seem to be working).
I have some nested objects:
Root ----Symbol (SPX)
| |------Day 1: Date: 2010-10-18, string "SPX meta"
| |------Day 2: Date: 2010-10-19, string "SPX meta"
|
|
|-----Symbol (IBM)
|------Day 1: Date: 2010-10-18, string "IBM meta"
|------Day 2: Date: 2010-10-19, string "IBM meta"
I create two symbols:
Symbol sym1 = new Symbol("SPX");
Symbol sym2 = new Symbol("IBM");
I then create some trading days:
// SPX
TradingDay day1 = new TradingDay(new DateTime(2010, 10, 18), "SPX meta");
TradingDay day2 = new TradingDay(new DateTime(2010, 10, 19), "SPX meta");
// IBM
TradingDay day3 = new TradingDay(new DateTime(2010, 10, 18), "IBM meta");
TradingDay day4 = new TradingDay(new DateTime(2010, 10, 19), "IBM meta");
I then assign a couple of days to each symbols:
sym1.AssignTradingDay(day1);
sym1.AssignTradingDay(day2);
sym2.AssignTradingDay(day3);
sym2.AssignTradingDay(day4);
I then persist it to the db4o object database:
// Store in the database.
db4o.db.Store(sym1);
db4o.db.Store(sym2);
db4o.db.Commit();
Pretty simple so far.
I check the database with "db4o Object Manager Enterprise", and sure enough, there is two symbols, and if I click on each symbol, each one contains two days.
Now, I do a LINQ query to pull the data out:
var daysForSymbolS1 = from Symbol s in db4o.db
from TradingDay t in db4o.db
where (s.SymbolGlobal == "IBM"
&& t.Date == new DateTime(2010, 10, 19))
select new
{
s.SymbolGlobal,
t.Date,
t.Meta
};
foreach (var d in daysForSymbolS1)
{
Console.WriteLine("{0} - {1} - {2}", d.SymbolGlobal, d.Date.Date, d.Meta);
}
And, something weird happens:
IBM - 10/19/2010 12:00:00 AM - SPX meta // This line should not appear because we have specified "IBM" in the filter.
IBM - 10/19/2010 12:00:00 AM - IBM meta
Despite the fact that I specified that it should only return data for "SPX" its returning data from "IBM" as well.
Am I doing anything obviously wrong?
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您没有发布类的确切定义,但您目前正在您的类中执行笛卡尔积 Linq 查询 - 您正在创建每种可能的组合,而您实际上只想要“匹配”组合(因为您的模式中的交易日由于某种原因似乎与符号相关联)。相反,您应该做的是加入,例如:
You didn't post the exact definition of your classes but you are currently doing a cartesian product in your Linq query - you are creating every possible combination whereas you really only want "matching" combinations (since a trading day in your schema for some reason seems to be associated with a symbol). What you should do instead is a join, something like: