PHP 的 imagecreatefromstring 函数在 Amazon Linux Server 上不起作用

发布于 2024-10-18 20:09:01 字数 1944 浏览 2 评论 0原文

我创建了一个脚本，其中 ai 必须使用 64 位编码字符串在运行时创建图像。im 使用 PHP 的 imagecreatefromstring 函数，但它可以在我的基于 Windows XAMPP 的 PHP 中工作，但不能在我部署在 Amazon 云上运行的云端应用程序上工作Linux 的 SUSE 版本。

你能给我任何建议来解决这个问题吗？或者是否有任何其他函数能够从传递给它的编码字符串创建图像。

感谢 adv

我正在使用以下代码

<?php
         require ('../dbconfig/dbConfig.php');

    $gameId = $_POST["gameId"];
    $username = $_POST['email'];
    $imagedata =  $_POST['imagedata'];

    $uploaddir = './../blogdata/i/'; 

    $countSql =  mysql_query("select  max(_id) as fileName  from blog_data ");

    while($rowCommentData = mysql_fetch_assoc($countSql))
    {
        $num = $rowCommentData["fileName"];
        $file = ++$num.".png";
        $filedb = $uploaddir .$file;
    }


   /* $imagedata= 'iVBORw0KGgoAAAANSUhEUgAAABwAAAASCAMAAAB/2U7WAAAABl'
               . 'BMVEUAAAD///+l2Z/dAAAASUlEQVR4XqWQUQoAIAxC2/0vXZDr'
               . 'EX4IJTRkb7lobNUStXsB0jIXIAMSsQnWlsV+wULF4Avk9fLq2r'
               . '8a5HSE35Q3eO2XP1A1wQkZSgETvDtKdQAAAABJRU5ErkJggg==';*/

    $imagedata= base64_decode($imagedata);

    if(($img = @imagecreatefromstring($imagedata)) !== FALSE) 
    {

            if(imagepng($img,$filedb))
            {       
                    imagedestroy($img);

                    $sql="Insert into blog_data (game_id,text,type,username)".
                                   "Values('$gameId','$file','i','$username')";

                    $result=mysql_query($sql);

                    if($result == 1)
                    {
                        echo $file; 
                    }
                    else
                    {
                        echo "error2";
                    }
            } 
            else {
                echo "error1";
            }               
                   }
    else
    { 
         echo "error0";
    }

？>

通过运行 PHP info 那里我得到了这个信息在此处输入图像描述

原文

I have created a script in which a i have to create a image at runtime using a 64bitencoded string .i m using imagecreatefromstring function of PHP but it works in my Windows XAMPP based PHP , but not on my cloud side applications which i deployed on Amazon cloud running SUSE version of Linux.

Can u give me any suggestion to overcome the problem.
Or is there any other function which is capable to create the image from the encoded string passed to it.

Thanks in adv

I am using following code

<?php
         require ('../dbconfig/dbConfig.php');

    $gameId = $_POST["gameId"];
    $username = $_POST['email'];
    $imagedata =  $_POST['imagedata'];

    $uploaddir = './../blogdata/i/'; 

    $countSql =  mysql_query("select  max(_id) as fileName  from blog_data ");

    while($rowCommentData = mysql_fetch_assoc($countSql))
    {
        $num = $rowCommentData["fileName"];
        $file = ++$num.".png";
        $filedb = $uploaddir .$file;
    }


   /* $imagedata= 'iVBORw0KGgoAAAANSUhEUgAAABwAAAASCAMAAAB/2U7WAAAABl'
               . 'BMVEUAAAD///+l2Z/dAAAASUlEQVR4XqWQUQoAIAxC2/0vXZDr'
               . 'EX4IJTRkb7lobNUStXsB0jIXIAMSsQnWlsV+wULF4Avk9fLq2r'
               . '8a5HSE35Q3eO2XP1A1wQkZSgETvDtKdQAAAABJRU5ErkJggg==';*/

    $imagedata= base64_decode($imagedata);

    if(($img = @imagecreatefromstring($imagedata)) !== FALSE) 
    {

            if(imagepng($img,$filedb))
            {       
                    imagedestroy($img);

                    $sql="Insert into blog_data (game_id,text,type,username)".
                                   "Values('$gameId','$file','i','$username')";

                    $result=mysql_query($sql);

                    if($result == 1)
                    {
                        echo $file; 
                    }
                    else
                    {
                        echo "error2";
                    }
            } 
            else {
                echo "error1";
            }               
                   }
    else
    { 
         echo "error0";
    }

By running PHP info there i got this information
enter image description here

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