在python中查找当前时间间隔？

发布于 2024-10-18 11:51:35 字数 280 浏览 6 评论 0原文

如何在 python 中找到最近的 15（或 10）分钟间隔？例如，

>>> datetime.datetime.now()
datetime.datetime(2011, 2, 22, 15, 43, 18, 424873)

我想要当前 15 分钟间隔（15:30-15:44），所以我想将上面的日期时间转换为

datetime.datetime(2011, 2, 22, 15, 30, 00, 00)

原文

How can I find the nearest 15 (or 10) minute interval in python ?
e.g.

>>> datetime.datetime.now()
datetime.datetime(2011, 2, 22, 15, 43, 18, 424873)

I'd like the current 15 minute interval (15:30-15:44) so I'd like to transform the above datetime to a

datetime.datetime(2011, 2, 22, 15, 30, 00, 00)

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诺曦 2024-10-25 11:51:35

对我来说最简单的方法：

from datetime import datetime, timedelta
now = datetime.now()
now = now - timedelta(minutes = now.minute % 15, seconds = now.second, microseconds = now.microsecond )

希望有帮助。

Quite the easiest way to me:

from datetime import datetime, timedelta
now = datetime.now()
now = now - timedelta(minutes = now.minute % 15, seconds = now.second, microseconds = now.microsecond )

Hope that'll help.

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梦里人 2024-10-25 11:51:35

我认为对于这种情况，使用 replace 比 timedelta：

>>> import datetime
>>> now = datetime.datetime.now()
>>> now.replace(minute=(now.minute - (now.minute % 15)), second=0, microsecond=0)
datetime.datetime(2012, 3, 23, 11, 15)
>>>

I think for this case using replace is more straightforward than timedelta:

>>> import datetime
>>> now = datetime.datetime.now()
>>> now.replace(minute=(now.minute - (now.minute % 15)), second=0, microsecond=0)
datetime.datetime(2012, 3, 23, 11, 15)
>>>

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