无法在 scala 上初始化类异常（可能是 squeryl bug）

发布于 2024-10-18 08:50:32 字数 1580 浏览 6 评论 0原文

我正在使用 scala 2.8.1、scalatra 2.0.0.M2、squeryl 2.8.0 和 scalate 2.0.0 和 sbt 开发一个 Web 应用程序，但

我遇到了问题，显然是模型或模式类。当我运行测试时，我得到：

java.lang.NoClassDefFoundError: Could not initialize class org.mycompany.myproject.model.myschema

如果我尝试在 sbt 的控制台上快速运行以下代码，我会得到一个错误：

import org.mycompany.myproject.model.myschema
myschema.mytable

错误：

java.lang.RuntimeException: Could not deduce Option[] type of field 'field1' of class org.mycompany.myproject.model.myotherclass

正如我所期望的，无论我尝试在该模式上调用什么方法，都会弹出错误。

现在，这是我的架构在该表声明附近的样子：

object myschema extends Schema {
  val myotherclasses = table[myotherclass]
  val otherClassManyToMany = manyToManyRelation(yetanotherclass, mytables).
       via[myotherclass]((e,ssr, sse) => (e.id === sse.leftId, sse.rightId === ssr.id))
...
}

这是我的代码表的样子：

class myotherclass(
  val rightId: Long,
  val field1: Option[Long],
  val field2: Option[Long],
  val foreiginKey: Long,
  val leftId: Long) extends KeyedEntity[CompositeKey2[Long, Long]] {
  def id ={compositeKey(sesestacao, sessensor)}
}

最后是我的 sql 定义：

create table telemetria.myotherclass (
  rightId numeric(8,0) references telemetria.estacao(estcodigo),
  field1 numeric(8,0),
  field2 numeric(8,0),
  foreiginKey smallint references myschema.thirdtable(idOfThird),
  leftId smallint references myschema.yetanotherclass(id),
  primary key (rightId, leftId)
);

我还没有将第三个表映射到我的代码中。可能发生什么事？

原文

I am developing a web application with scala 2.8.1, scalatra 2.0.0.M2, squeryl 2.8.0 and scalate 2.0.0 and sbt

I am having a problem with, apparently a model or the schema class. When I run my tests I get a:

java.lang.NoClassDefFoundError: Could not initialize class org.mycompany.myproject.model.myschema

If I try to run the following code on sbt's console-quick I get an error:

import org.mycompany.myproject.model.myschema
myschema.mytable

Error:

java.lang.RuntimeException: Could not deduce Option[] type of field 'field1' of class org.mycompany.myproject.model.myotherclass

As I have expected the error pops up no matter what method I try to invoke on that schema.

Now here is how my schema looks like near that table declaration:

object myschema extends Schema {
  val myotherclasses = table[myotherclass]
  val otherClassManyToMany = manyToManyRelation(yetanotherclass, mytables).
       via[myotherclass]((e,ssr, sse) => (e.id === sse.leftId, sse.rightId === ssr.id))
...
}

This is how my code table looks like:

class myotherclass(
  val rightId: Long,
  val field1: Option[Long],
  val field2: Option[Long],
  val foreiginKey: Long,
  val leftId: Long) extends KeyedEntity[CompositeKey2[Long, Long]] {
  def id ={compositeKey(sesestacao, sessensor)}
}

And finally my sql definition:

create table telemetria.myotherclass (
  rightId numeric(8,0) references telemetria.estacao(estcodigo),
  field1 numeric(8,0),
  field2 numeric(8,0),
  foreiginKey smallint references myschema.thirdtable(idOfThird),
  leftId smallint references myschema.yetanotherclass(id),
  primary key (rightId, leftId)
);

I have not mapped the thirdtable into my code. What could be going on?

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蒗幽 2024-10-25 08:50:32

使用 Squeryl，如果有任何 Option[_] 类型的字段，则必须定义默认构造函数。因此，对于这种情况，您将

def this() = this(0l, Some(0l), Some(0l), 0l, 0l)

使用 myotherclass 以便 Squeryl 可以找出 Option[_] 列的类型。请参阅此处 http:// squeryl.org/schema-definition.html

With Squeryl, you have to define a default constructor if you have any fields of type Option[_]. So, for this case you would have

def this() = this(0l, Some(0l), Some(0l), 0l, 0l)

on myotherclass so that Squeryl can figure out the type of the Option[_] columns. See the section labeled Nullable columns are mapped with Option[] fields here http://squeryl.org/schema-definition.html

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