重定向 C++溪流

发布于 2024-10-18 01:56:15 字数 755 浏览 3 评论 0原文

我有一个方法搜索，我想提供输入流，然后将输出放在输出流上。

void search(std::istream & is, std::ostream & os);

现在我想用 cin/cout 来做这件事。从命令提示符处：

a.out < input_file.txt

在 main 中，我尝试通过将 cin/cout 传递给 search() 方法来执行此操作。

X.search(std::cin, std::cout);

编译和链接（XCode）时出现以下错误：

Line Location Tool:0: collect2: ld returned 1 exit status
Line Location Tool:0: symbol(s) not found
Line Location Tool:0: _main in main.o
Line Location Tool:0: "X::search(std::basic_istream<char, std::char_traits<char> >&,
   std::basic_ostream<char, std::char_traits<char> >&)", referenced from:

我需要为 cin/cout 做些什么不同的事情吗？我不知道如何解决这个错误。

原文

I have a method search that I want to feed an input stream and then put output on an output stream.

void search(std::istream & is, std::ostream & os);

For now I'd like to do this with cin/cout. From the command prompt:

a.out < input_file.txt

In main, I try to do this by passing cin/cout to the search() method.

X.search(std::cin, std::cout);

I get the following error when I compile and link (XCode):

Line Location Tool:0: collect2: ld returned 1 exit status
Line Location Tool:0: symbol(s) not found
Line Location Tool:0: _main in main.o
Line Location Tool:0: "X::search(std::basic_istream<char, std::char_traits<char> >&,
   std::basic_ostream<char, std::char_traits<char> >&)", referenced from:

Is there anything different I need to be doing for cin/cout? I cannot figure out how to resolve this error.

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夕嗳→ 2024-10-25 01:56:15

这在 xcode 中编译并运行良好（c++ cmdline 新项目向导），看起来您缺少 #include;或 main，或 X 类的定义。

#include <iostream>

void foo( std::istream &is, std::ostream &os )
{
    std::string s;
    while ( getline( is, s, '\n' ) )
    {
        os << s;
    }
}

int main (int argc, char * const argv[]) {
    // insert code here...
    std::cout << "Hello, World!\n";
    foo( std::cin, std::cout );

    return 0;
}

This compiles and runs fine for me in xcode (c++ cmdline new project wizard), looks like you're missing an #include <iostream> or main, or a definition of your X class.

#include <iostream>

void foo( std::istream &is, std::ostream &os )
{
    std::string s;
    while ( getline( is, s, '\n' ) )
    {
        os << s;
    }
}

int main (int argc, char * const argv[]) {
    // insert code here...
    std::cout << "Hello, World!\n";
    foo( std::cin, std::cout );

    return 0;
}

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