如何将名称值数据添加到 Android HTTP 文件上传 POST 请求

发布于 2024-10-17 16:43:42 字数 2889 浏览 1 评论 0原文

我有一个 Android 照片上传脚本,如果我使用 $_GET 读取一些数据,上传效果很好,我想使用所有 $_POST。问题是我需要附加数据来执行发布的请求,以包含基本名称值对以及文件上传。如果我让服务器使用 $_GET 并在 url 字符串中添加额外的数据,我就可以让它工作,但我想使用 post.有没有办法在文件上传中对服务器可以使用 $_POST 读取的其他发布数据进行编码。这是函数,注意 URL 字符串,我试图获取变量 api_key、session_key 和要在 POST 请求中发送的方法。

public void uploadPhoto(FileInputStream fileInputStream, String sessionKey) throws IOException, ClientProtocolException {

    URL connectURL = new URL(API_URL +"?api_key=" +API_KEY+ "&session_key=" + sessionKey + "&method=" + ApiMethods.UPLOAD_PHOTO); //server ignores this data

    String lineEnd = "\r\n";
    String twoHyphens = "--";
    String boundary = "*****";

    HttpURLConnection conn = (HttpURLConnection) connectURL.openConnection();

    // Allow Inputs
    conn.setDoInput(true);

    // Allow Outputs
    conn.setDoOutput(true);

    // Don't use a cached copy.
    conn.setUseCaches(false);

    // Use a post method.
    conn.setRequestMethod("POST");

    conn.setRequestProperty("Connection", "Keep-Alive");

    conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+ boundary);

    DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

    dos.writeBytes(twoHyphens + boundary + lineEnd);
    dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""+ "file.png" + "\"" + lineEnd);
    dos.writeBytes(lineEnd);


    // create a buffer of maximum size

    int bytesAvailable = fileInputStream.available();
    int maxBufferSize = 1028;
    int bufferSize = Math.min(bytesAvailable, maxBufferSize);
    byte[] buffer = new byte[bufferSize];

    // read file and write it into form...

    int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
    while (bytesRead > 0) {
        dos.write(buffer, 0, bufferSize);
        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        /*
         * dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary +
         * twoHyphens + lineEnd);
         */
    }

    // send multipart form data necesssary after file data...
    dos.writeBytes(lineEnd);
    dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
    dos.flush();
    // Log.d(TAG, "  dos5: " + dos.toString());
    InputStream is = conn.getInputStream();
    // retrieve the response from server
    int ch;

    StringBuffer b = new StringBuffer();
    while ((ch = is.read()) != -1) {
        b.append((char) ch);
    }
    String s = b.toString();
    dos.close();

}

编辑 我认为每个添加的参数都需要类似以下内容

    dos.writeBytes("--" + boundary + lineEnd);
    dos.writeBytes("Content-Disposition: form-data;name=api_key=" + lineEnd + lineEnd + API_KEY);
    dos.writeBytes(lineEnd);
    dos.writeBytes("--" + boundary + "--" + lineEnd);

I have an android photo upload script that uploads fine if I use $_GET to read some data, I want to use all $_POST. The problem is I need to append data do the posted request to include basic name value pairs along with the file upload. I can get this to work if I have the server use $_GET and just add the extra data in the url string, but I want to use post. Is there a way to encode other post data in the file upload that the server can read using $_POST. Heres the function, notice the URL string where, I'm trying to get the variables api_key,session_key, and method to be sent in the POST request.

public void uploadPhoto(FileInputStream fileInputStream, String sessionKey) throws IOException, ClientProtocolException {

    URL connectURL = new URL(API_URL +"?api_key=" +API_KEY+ "&session_key=" + sessionKey + "&method=" + ApiMethods.UPLOAD_PHOTO); //server ignores this data

    String lineEnd = "\r\n";
    String twoHyphens = "--";
    String boundary = "*****";

    HttpURLConnection conn = (HttpURLConnection) connectURL.openConnection();

    // Allow Inputs
    conn.setDoInput(true);

    // Allow Outputs
    conn.setDoOutput(true);

    // Don't use a cached copy.
    conn.setUseCaches(false);

    // Use a post method.
    conn.setRequestMethod("POST");

    conn.setRequestProperty("Connection", "Keep-Alive");

    conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+ boundary);

    DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

    dos.writeBytes(twoHyphens + boundary + lineEnd);
    dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""+ "file.png" + "\"" + lineEnd);
    dos.writeBytes(lineEnd);


    // create a buffer of maximum size

    int bytesAvailable = fileInputStream.available();
    int maxBufferSize = 1028;
    int bufferSize = Math.min(bytesAvailable, maxBufferSize);
    byte[] buffer = new byte[bufferSize];

    // read file and write it into form...

    int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
    while (bytesRead > 0) {
        dos.write(buffer, 0, bufferSize);
        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
        /*
         * dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary +
         * twoHyphens + lineEnd);
         */
    }

    // send multipart form data necesssary after file data...
    dos.writeBytes(lineEnd);
    dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
    dos.flush();
    // Log.d(TAG, "  dos5: " + dos.toString());
    InputStream is = conn.getInputStream();
    // retrieve the response from server
    int ch;

    StringBuffer b = new StringBuffer();
    while ((ch = is.read()) != -1) {
        b.append((char) ch);
    }
    String s = b.toString();
    dos.close();

}

EDIT
I'm thinking something like the following is needed for each added param

    dos.writeBytes("--" + boundary + lineEnd);
    dos.writeBytes("Content-Disposition: form-data;name=api_key=" + lineEnd + lineEnd + API_KEY);
    dos.writeBytes(lineEnd);
    dos.writeBytes("--" + boundary + "--" + lineEnd);

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(1

少女净妖师 2024-10-24 16:43:42

有一些现有的开放库支持 mime 编码,这可能会节省您一些时间。我在一些我为发布而编写的内容中使用了这里的代码:

http://www.softwarepassion.com/android-series-get-post-and-multipart-post-requests/

您可以从这里获取 apache-mime4j 和 httpmime 库:

http://code.google.com/ p/osmdroid/source/browse/trunk/osmdroid-google-wrapper/lib/?r=769

There are some existing open libraries that support mime encoding which might save you some time. I used the code from here in some stuff I hacked up for posting:

http://www.softwarepassion.com/android-series-get-post-and-multipart-post-requests/

You can get the apache-mime4j and httpmime libraries from here:

http://code.google.com/p/osmdroid/source/browse/trunk/osmdroid-google-wrapper/lib/?r=769

~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文