GWT FormPanel 并将数据提交到服务器

发布于 2024-10-17 14:30:31 字数 541 浏览 6 评论 0原文

我有一个 GWT 应用程序，我需要将 FormPanel 放在文本框 (TextBox) 中。（解决一些样式问题）

编辑： 样式问题是：我们正在使用一些预构建的样式表，它们通过 HTML 标记名称放置样式..因此我们需要放置一个 form 标记来包装一些组件以便能够读取风格！

问题是，在 KeyPress 事件中，我注意到页面中出现了加载。尽管结果返回ajaxaly，就好像没有发生客户端-服务器旅行一样。

问题是，如何去掉这行服务器呢？

注意：我只是将组件包装到表单面板中，我没有设置它的任何属性：

FormPanel formPanel = new FormPanel();
CaptionPanel captionPanel = new CaptionPanel();
formPanel.add(captionPanel);
captionPanel.add(horizontalPanel);
verticalPanel.add(formPanel);

谢谢。

原文

I've a GWT app that I need to put FormPanel to wrap a textbox (TextBox). (to solve some styling issue)

EDIT:
The style issue is that: we are using some pre-build style sheet which put styles by HTML tag names .. so we need to put a form tag to wrap some components in order to be able to read the styles!

the problem is, on the KeyPress event, I notice there is a loading in the page appears. although the result returns ajaxaly as if there's no client-server trip happened.

The question is, How to remove this trip to server?

NOTE: i am just wrapping the componenets into the formpanel, I've not set any properties of it:

FormPanel formPanel = new FormPanel();
CaptionPanel captionPanel = new CaptionPanel();
formPanel.add(captionPanel);
captionPanel.add(horizontalPanel);
verticalPanel.add(formPanel);

Thanks.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

半世晨晓 2024-10-24 14:30:31

从您的问题来看，尚不清楚是什么原因导致服务器访问。但如果是 FormPanel 导致了此问题，我会将 FormPanel 的实例化更改为以下内容：

FormPanel formPanel = new FormPanel() {
    public boolean onFormSubmit() { return false; }
};

这应该相当于以下 html，这将使表单无法提交：

<form onsubmit="return false">

如果这不能解决问题，那么您'您需要进行更多调试才能查看服务器被调用的位置。适用于 Firefox 的 Tamper Data 插件可能会有所帮助为了这。

From your question, it isn't clear that what is causing the trip to the server. But if it is the FormPanel that's causing this, I would change the instantiation of the FormPanel to the following:

FormPanel formPanel = new FormPanel() {
    public boolean onFormSubmit() { return false; }
};

This should be the equivalent of the following html, which will keep the form from submitting:

<form onsubmit="return false">

If this doesn't fix it, you'll need to do some more debugging to see where the server is being called. The Tamper Data plug-in for Firefox might be of help for this.

回复收藏 0 原文