查找尝试连接 ServerSocket 的程序的 IP

发布于 2024-10-17 13:22:08 字数 501 浏览 7 评论 0原文

尽管我进行了搜索，但找不到答案。

假设我有以下 Java 代码：

    ServerSocket serve = null;

    try {
        server = new ServerSocket(5567);
    } catch (IOException e) {
        System.err.println("Problem with port 5567");
        System.exit(1);
    }

    Socket clientSocket = null;
    try {
        clientSocket = server.accept();
    } catch (IOException e) {
        System.exit(1);
    }

当调用 server.accept() 时，程序会阻塞，直到有人连接到我的服务器。有没有办法找到连接到我的服务器的程序/用户的IP？

原文

Although I searched about it I couldn't find an answer.

Let's say I have the following Java code:

    ServerSocket serve = null;

    try {
        server = new ServerSocket(5567);
    } catch (IOException e) {
        System.err.println("Problem with port 5567");
        System.exit(1);
    }

    Socket clientSocket = null;
    try {
        clientSocket = server.accept();
    } catch (IOException e) {
        System.exit(1);
    }

When server.accept() is being called the program blocks until someone connects to my server. Is there a way, to be able to find the IP of the program/user who connects to my server?

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遮云壑 2024-10-24 13:22:08

尝试

Socket clientSocket = null;
    try {
        clientSocket = server.accept();
        System.out.println("Connected from " + clientSocket .getInetAddress() + " on port "
             + clientSocket .getPort() + " to port " + clientSocket .getLocalPort() + " of "
             + clientSocket .getLocalAddress());
    } catch (IOException e) {
        System.exit(1);
    }

Try

Socket clientSocket = null;
    try {
        clientSocket = server.accept();
        System.out.println("Connected from " + clientSocket .getInetAddress() + " on port "
             + clientSocket .getPort() + " to port " + clientSocket .getLocalPort() + " of "
             + clientSocket .getLocalAddress());
    } catch (IOException e) {
        System.exit(1);
    }

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