如何在 elisp 中捕获 shell 命令的标准输出？
我想在 Emacs 中运行 shell 命令并将完整输出捕获到变量中。有办法做到这一点吗？例如，我希望能够通过以下方式将 hello-string 设置为 "hello"：
(setq hello-string (capture-stdout-of-shell-command "/bin/echo hello"))
函数 capture-stdout-of-shell -command 存在，如果存在，它的真实名称是什么？
I want to run a shell command within Emacs and capture the full output to a variable. Is there a way to do this? For example, I would like to be able to set hello-string to "hello" in the following manner:
(setq hello-string (capture-stdout-of-shell-command "/bin/echo hello"))
Does the function capture-stdout-of-shell-command exist, and if so what is its real name?
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shell-command- to-string满足您的目的吗？例如：
Does
shell-command-to-stringmeet your purpose?For example:
我有一个建议可以扩展伊势紫藤的答案。尝试使用类似这样的内容：
这应该将字符串“hello”设置为 my_shell_output 的值，但要干净。使用
(substring)可以消除 emacs 调用 shell 命令时经常出现的尾随\n。它让我在 Windows 上运行的 emacs 中感到困扰，并且可能也会在其他平台上发生。I have a suggestion to made that extends Ise Wisteria's answer. Try using something like this:
This should set the string
"hello"as the value ofmy_shell_output, but cleanly. Using(substring)eliminates the trailing\nthat tends to occur when emacs calls out to a shell command. It bothers me in emacs running on Windows, and probably occurs on other platforms as well.最后，“git log”“--reverse”选项派上了用场）。使用最初始提交时的当前缓冲区文件打开缓冲区。
而关于这个问题
Finally, the "git log" "--reverse" option came in handy ). Open a buffer with the current buffer file as of the most initial commit.
And on the question of