如何在 PL/SQL 过程 ORACLE 中使用 XPATH 读取 XML 中的属性值？
我有一个如下所示的 xml：
<!-- XML-Code -->
indoc := '
<Students>
<Student Enrolled = "true">
<SID>12456</SID>
</Student>
<Student Enrolled = "false">
<SID>12345</SID>
</Student>
</Students>';
<!-- XML Code -->
indomdoc := dbms_xmldom.newDomDocument(indoc);
我正在使用
dbms_xslprocessor.selectNodes(dbms_xmldom.makeNode(indomdoc),
'//Student[@Enrolled="True"]');
This 返回我属性 Enrolled 为 true 的学生值。
我再次用来
dbms_xslprocessor.selectNodes(dbms_xmldom.makeNode(indomdoc),
'//Student[@Enrolled="False"]');
获取所有尚未注册的学生。
但我想知道是否有任何方法可以使用 xsl 处理器查找已注册属性的值，而不是直接给出 @Enrolled="True" 和 @Enrolled="False".
I have an xml like the following:
<!-- XML-Code -->
indoc := '
<Students>
<Student Enrolled = "true">
<SID>12456</SID>
</Student>
<Student Enrolled = "false">
<SID>12345</SID>
</Student>
</Students>';
<!-- XML Code -->
indomdoc := dbms_xmldom.newDomDocument(indoc);
I am using
dbms_xslprocessor.selectNodes(dbms_xmldom.makeNode(indomdoc),
'//Student[@Enrolled="True"]');
This is returning me the values Of Students with attribute Enrolled as true.
and again I am using
dbms_xslprocessor.selectNodes(dbms_xmldom.makeNode(indomdoc),
'//Student[@Enrolled="False"]');
to get all students who are not enrolled yet.
But I want to know is there any way to find the value of enrolled attribute using xsl processor, rather than directly giving like @Enrolled="True" and @Enrolled="False".
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XPath 表达式
//Student/@Enrolled将为您提供Enrolled属性的所有值。XPath expression
//Student/@Enrolledwill give you all the values of theEnrolledattribute.使用引用属性值的 XPath 表达式怎么样？
我是否遗漏了你问题的某些部分？
How about using an XPath expression referencing the attribute value?
Am I missing some part of your problem?