Xpath 不是通过 Powershell Select-Xml 中的运算符
我正在使用 csproj 文件，并且正在尝试编写一个 cmdlet 来提取项目文件引用的所有文件。这将包括所有 Compile、EmbeddedResource、Resource、Content 和 None 元素（更重要的是它们的 @Include 值），但我特别想排除 Reference 元素，因为它们引用 dll，而这与我无关。
我没有太多的经验，但我认为我想要的 xpath 表达式看起来像这样
$projectFile | Select-Xml -namespace @{msb="http://schemas.microsoft.com/developer/msbuild/2003"} -xpath "//msb:ItemGroup/*[not(self::node() = msb:Reference) and @Include]"
但是，一旦我尝试引入 self::node() 我的表达式就不会返回任何节点。我不是 100% 确定 self::node() 是执行此操作的正确方法。知道我要更改什么才能使其在概念上返回“所有包含不是 Reference 元素的节点的属性值吗？”
I'm working with csproj files, and I'm trying to write a cmdlet that extracts all of the files referenced by a project file. This will include all of the Compile, EmbeddedResource, Resource, Content, and None elements (more importantly, their @Include values) but I specifically want to exclude the Reference elements as they refer to dlls, which aren't of concern to me.
I don't have a ton of experience, but I would think the xpath expression I would want would look something like this
$projectFile | Select-Xml -namespace @{msb="http://schemas.microsoft.com/developer/msbuild/2003"} -xpath "//msb:ItemGroup/*[not(self::node() = msb:Reference) and @Include]"
However, as soon as I try to introduce the self::node() my expression returns no nodes. I'm not 100% sure that self::node() is the right way to be doing this though. Any idea what I would change to make it return, conceptually, "all Include attribute values for nodes that are not Reference elements that are child elements of an ItemGroup element?"
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我认为您需要：
含义：
msb:ItemGroup的任何子项的所有Inlude属性（msb 除外）：参考，在整个文档中I think that you need:
Meaning: all the
Includeattributes of any child ofmsb:ItemGroupexcept formsb:Reference, in the whole document