sysinfo 系统调用在 Linux 上返回错误的负载平均值

发布于 2024-10-17 05:45:06 字数 1300 浏览 1 评论 0原文

我有一个 C 程序,可以打印一些系统统计信息。

#include <sys/sysinfo.h>
#include <stdio.h>

int main() {
  int days, hours, mins;
  struct sysinfo sys_info;

  if(sysinfo(&sys_info) != 0)
    perror("sysinfo");

  // Uptime
  days = sys_info.uptime / 86400;
  hours = (sys_info.uptime / 3600) - (days * 24);
  mins = (sys_info.uptime / 60) - (days * 1440) - (hours * 60);

  printf("Uptime: %ddays, %dhours, %dminutes, %ldseconds\n",
                      days, hours, mins, sys_info.uptime % 60);

  // Load Averages for 1,5 and 15 minutes
  printf("Load Avgs: 1min(%ld) 5min(%ld) 15min(%ld)\n",
          sys_info.loads[0], sys_info.loads[1], sys_info.loads[2]);

  printf("Total Ram: %lluk\tFree: %lluk\n",
                sys_info.totalram *(unsigned long long)sys_info.mem_unit / 1024,
                sys_info.freeram *(unsigned long long)sys_info.mem_unit/ 1024);


  // Number of processes currently running.
  printf("Number of processes: %d\n", sys_info.procs);

  return 0;
}

我的问题是负载平均值与 /proc/loadavg 不同,

./a.out 
Uptime: 1days, 4hours, 1minutes, 16seconds
Load Avgs: 1min(13248) 5min(14880) 15min(11840)
Total Ram: 2052956k Free: 188104k
Number of processes: 265

为什么?我正在打印 13248,但“top”或“cat /proc/loadavg”给出 0.24。问题是什么?

I have a C program that prints some system statistics.

#include <sys/sysinfo.h>
#include <stdio.h>

int main() {
  int days, hours, mins;
  struct sysinfo sys_info;

  if(sysinfo(&sys_info) != 0)
    perror("sysinfo");

  // Uptime
  days = sys_info.uptime / 86400;
  hours = (sys_info.uptime / 3600) - (days * 24);
  mins = (sys_info.uptime / 60) - (days * 1440) - (hours * 60);

  printf("Uptime: %ddays, %dhours, %dminutes, %ldseconds\n",
                      days, hours, mins, sys_info.uptime % 60);

  // Load Averages for 1,5 and 15 minutes
  printf("Load Avgs: 1min(%ld) 5min(%ld) 15min(%ld)\n",
          sys_info.loads[0], sys_info.loads[1], sys_info.loads[2]);

  printf("Total Ram: %lluk\tFree: %lluk\n",
                sys_info.totalram *(unsigned long long)sys_info.mem_unit / 1024,
                sys_info.freeram *(unsigned long long)sys_info.mem_unit/ 1024);


  // Number of processes currently running.
  printf("Number of processes: %d\n", sys_info.procs);

  return 0;
}

My problem is that the load average values are different than /proc/loadavg

./a.out 
Uptime: 1days, 4hours, 1minutes, 16seconds
Load Avgs: 1min(13248) 5min(14880) 15min(11840)
Total Ram: 2052956k Free: 188104k
Number of processes: 265

Why? I am printing 13248 but "top" or "cat /proc/loadavg" gives 0.24. What is the problem?

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评论(1

凉城 2024-10-24 05:45:06

该调用不会返回“错误”值。请注意,该类型是整数,因此它不能返回正常运行时间打印的浮点数。

请参阅此线程了解研究如何解释返回值以及如何转换为更熟悉的浮点数。

我的猜测(在阅读链接之前)是它只是按比例放大了 65,535 (216),这似乎也是他们发现的。因此,除以 65536.0,或者为了更清晰(如评论中指出的那样),请使用 SI_LOAD_SHIFT 常量并除以 (float)(1 << SI_LOAD_SHIFT)

The call doesn't return the "wrong" values. Note that the type is integer, so it can't be intended to return the floating-point numbers printed by uptime.

See this thread for an investigation in how to interpret the returned values, and how to convert to the more familiar floats.

My guess (before reading the link) was that it's just represented as scaled up by 65,535 (216), and that seems to be what they found, too. So divide by 65536.0, or to be way cleaner (as pointed out in a comment) use the SI_LOAD_SHIFT constant and divide by (float)(1 << SI_LOAD_SHIFT).

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