鼠标点击到达后窗口 WPF
我创建了一种“处理”对话框,它显示某个进程的进度。它包含一个进度条和一个标签。这是代码:
public class ProcessingDialog
{
FrontWindow win;
public ProcessingDialog(int min, int max, string initialMessage,string title, bool isContineous)
{
Thread th= new Thread(new ThreadStart(delegate()
{
win = new FrontWindow();
win.Title = title;
if (isContineous == false)
{
win.ProgressBarProgress.Minimum = min;
win.ProgressBarProgress.Maximum = max;
}
else
win.ProgressBarProgress.IsIndeterminate = true;
win.LabelStatus.Content = initialMessage;
win.ShowInTaskbar = false;
win.Topmost = true;
win.ShowDialog();
}
));
th.SetApartmentState(ApartmentState.STA);
th.Start();
}
public void Increment(int margin)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value+=margin; }), null); ;
}
public void Reset()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value=0; }), null); ;
}
public void ChangeMessage(string message)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.LabelStatus.Content=message; }), null); ;
}
public void Close()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.Close(); }), null); ;
}
}
这是 FrontWindow 的标记:
<Window x:Class="WpfApplicationUnleashed.FrontWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="FrontWindow" Height="165" Width="300" WindowStyle="ThreeDBorderWindow" WindowStartupLocation="CenterOwner" ResizeMode="NoResize">
<DockPanel>
<ProgressBar x:FieldModifier="public" x:Name="ProgressBarProgress" Height="15" Margin="20" DockPanel.Dock="Top" VerticalAlignment="Top"></ProgressBar>
<Label x:FieldModifier="public" x:Name="LabelStatus" Margin="10" VerticalAlignment="Top" HorizontalAlignment="Left" DockPanel.Dock="Bottom"></Label>
</DockPanel>
</Window>
这是我显示对话框的窗口。它只包含一个按钮,其单击事件是这样的:
private void button1_Click(object sender, RoutedEventArgs e)
{
ProcessingDialog pd = new ProcessingDialog(0, 10, "Starting", "Processing", false);
Thread.Sleep(1000);
pd.ChangeMessage("Step 1");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 2");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 3");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 4");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 5");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 6");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 7");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 8");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 9");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 10");
pd.Increment(1);
Thread.Sleep(1000);
pd.Close();
}
问题是,当显示它时,如果我再次单击该按钮,当对话框关闭时,它会再次打开。我的意思是它不会被单击,因为它是模态的,但它只是排队,当对话框关闭时,它会被单击。
我怎样才能防止这种情况发生?
I have created a sort of "processing" dialogbox which displays the progess of a certain process.It contains one progressbar and one Label. Here is the code:
public class ProcessingDialog
{
FrontWindow win;
public ProcessingDialog(int min, int max, string initialMessage,string title, bool isContineous)
{
Thread th= new Thread(new ThreadStart(delegate()
{
win = new FrontWindow();
win.Title = title;
if (isContineous == false)
{
win.ProgressBarProgress.Minimum = min;
win.ProgressBarProgress.Maximum = max;
}
else
win.ProgressBarProgress.IsIndeterminate = true;
win.LabelStatus.Content = initialMessage;
win.ShowInTaskbar = false;
win.Topmost = true;
win.ShowDialog();
}
));
th.SetApartmentState(ApartmentState.STA);
th.Start();
}
public void Increment(int margin)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value+=margin; }), null); ;
}
public void Reset()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value=0; }), null); ;
}
public void ChangeMessage(string message)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.LabelStatus.Content=message; }), null); ;
}
public void Close()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.Close(); }), null); ;
}
}
This is the markup for FrontWindow:
<Window x:Class="WpfApplicationUnleashed.FrontWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="FrontWindow" Height="165" Width="300" WindowStyle="ThreeDBorderWindow" WindowStartupLocation="CenterOwner" ResizeMode="NoResize">
<DockPanel>
<ProgressBar x:FieldModifier="public" x:Name="ProgressBarProgress" Height="15" Margin="20" DockPanel.Dock="Top" VerticalAlignment="Top"></ProgressBar>
<Label x:FieldModifier="public" x:Name="LabelStatus" Margin="10" VerticalAlignment="Top" HorizontalAlignment="Left" DockPanel.Dock="Bottom"></Label>
</DockPanel>
</Window>
And here is the Window from where I show the dialogbox.It just cantains one buttons whose click event is this:
private void button1_Click(object sender, RoutedEventArgs e)
{
ProcessingDialog pd = new ProcessingDialog(0, 10, "Starting", "Processing", false);
Thread.Sleep(1000);
pd.ChangeMessage("Step 1");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 2");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 3");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 4");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 5");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 6");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 7");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 8");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 9");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 10");
pd.Increment(1);
Thread.Sleep(1000);
pd.Close();
}
The problem is that when it's being shown, if i click the button again, when the dialogbox is closed, it opens again. I mean it does not get clicked because it's Modal, but it just queues up and when the dialogbox is closed, it gets clicked.
How can I prevent this from happening?
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(2)
也许将命令绑定到按钮并写入CanExecute 方法,如果命令已经在执行中,则阻止执行该命令。
Maybe bind a command to the button and write a CanExecute method which prevents the command from being executed if it is already in progress.
如果在前窗口打开时不打算使用后窗口,我会在加载的前窗口上设置一个事件以禁用后窗口,并在关闭时启用后窗口。
If the back window is not meant to be used while the front window is open, I would set an event on the frontwindow's loaded to disable the back window, and on close, enable the back window.