如何找出文本块中最常用的 2 个单词组合？

Question

如何从一段文本中找出我最常用的两个单词？换句话说，是否有一个在线或离线（或代码）工具，我可以在其中复制和粘贴文本，并输出我最常用的两个词频，例如：

从最常用到最少：

“猫”2.9％ “她说” 1.8% “去了” 1.2%

谢谢

Answer 1

1. 将文本分成两个单词对（使用 substr 和 strpos 来帮助您）

   • 使用 strpos 查找空格的第二个索引，然后使用开头和第二个空格索引之间的子字符串来获取两个单词对。
2. 将每一对添加到地图或集合中（该对将是键）并设置值（如果地图中已存在，则增加值）
3. 解析全文后，根据地图的大小计算百分比/set 和每对的值。

Answer 2

这很有趣，但我做了一些尝试，这应该让你开始，而不应该是你的答案。

这基本上是将单词分组为 2，将它们索引到数组中并递增找到的时间，最后转换为百分比:)

$data = 'In the first centuries of typesetting, quotations were distinguished merely by indicating the speaker, and this can still be seen in some editions of the Bible. During the Renaissance, quotations were distinguished by setting in a typeface contrasting with the main body text (often Italic type with roman, or the other way round). Block quotations were set this way at full size and full measure.
Quotation marks were first cut in type during the middle of the sixteenth century, and were used copiously by some printers by the seventeenth. In Baroque and Romantic-period books, they could be repeated at the beginning of every line of a long quotation. When this practice was abandoned, the empty margin remained, leaving an indented block quotation';

//Clean The Data from un required chars!
$data = preg_replace("/[^\w]/"," ",$data);

$segments = explode(" ",$data);
$indexes = array();

for($i=0;$i<count($segments);$i++)
{
   if($i == 0)
   {
      continue;
   }

   if(trim($segments[$i - 1]) != "" && trim($segments[$i]) != "")
   {
      $key = trim($segments[$i - 1]) . " " . trim($segments[$i]);
      if(array_key_exists($key,$indexes))
      {
          $indexes[$key]["count"]++;
      }else
      {
          $indexes[$key] = array(
              'count' => 1,
              'words' => $key
          );
      }
   }
}

//Change to the percentage:
$total_double_words = count($segments);
foreach($indexes as $id => $set)
{
    $indexes[$id]['percentage'] = number_format((($set['count']/ $total_double_words) * 100),2) . "%";
}

var_dump($indexes);

您可以在这里看到它：