从流中解析 C# 中的 XML

发布于 2024-10-16 19:19:26 字数 1515 浏览 1 评论 0原文

我尝试了多种方法,从 Linq 到将数据加载到 XML 文档,但我似乎无法返回我需要的结果。

这是示例 XML:

<serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message>

而且,这是我尝试做的:

StreamReader reader = new StreamReader(dataStream);
XmlDocument doc = new XmlDocument();
doc.LoadXml(reader.ReadToEnd());
XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable);
ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service");
ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common");
ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event");
XmlNode node = doc.SelectSingleNode("result",ns);

然而,由于某种原因,我似乎无法返回实际结果,根据上面的实际 xml,该结果应该是“成功”或“失败”。

我该怎么做?

I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need.

here's the example XML:

<serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message>

And, here's what i've tried to do:

StreamReader reader = new StreamReader(dataStream);
XmlDocument doc = new XmlDocument();
doc.LoadXml(reader.ReadToEnd());
XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable);
XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable);
ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service");
ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common");
ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event");
XmlNode node = doc.SelectSingleNode("result",ns);

Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above.

How can i do this?

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以往的大感动 2024-10-23 19:19:26

您的 xpath 查询不正确。

试试这个:

XmlNode node = doc.SelectSingleNode("//serv:result",ns);

或者

XmlNode node = doc.SelectSingleNode("serv:message/serv:header/serv:response/serv:result",ns);

your xpath query is not correct.

try this one :

XmlNode node = doc.SelectSingleNode("//serv:result",ns);

or

XmlNode node = doc.SelectSingleNode("serv:message/serv:header/serv:response/serv:result",ns);
如梦 2024-10-23 19:19:26

这有效:

XDocument doc = XDocument.Load(@"test.xml");
XNamespace serv = "http://www.webex.com/schemas/2002/06/service";
var result = doc.Descendants(serv + "result").First().Value;

This works:

XDocument doc = XDocument.Load(@"test.xml");
XNamespace serv = "http://www.webex.com/schemas/2002/06/service";
var result = doc.Descendants(serv + "result").First().Value;
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