匹配 MySQL 中的每个值至少一个
我有 2 个表，我想从一个表中选择条目，其中第二个表中有用于项目列表的条目。
例如：
条目
id=1 requirements=(1,2,3)
id=2 requirements=(1,3,5)
提交
id=1 entry=1 requirement=1
id=2 entry=2 requirement=2
id=3 entry=3 requirement=3
会选择条目 id=1，但不会条目 id=2（因此 WHERE IN不做这项工作）
*编辑实际数据集：
INSERT INTO submission (entry_id, requirement_id, submission_id)价值观 (17,1,1), (43,1,2), (57,0,3), (57,0,4), (1,1,5), (26,1,6), (40,1,7), (40,1,8), (40,1,9), (40,1,10), (85,1,11), (94,1,12), (114, 0, 13), (32,1,14), (34, 0, 15);
INSERT INTO entry (entry_id, category_id) 值 (1, 2), (2, 1), (3, 1), (4, 1), (5, 2), (6, 1), (7, 1), (8, 1), (9, 1), (10, 1), (11, 1), (12, 1), (13, 1), (14, 1), (15, 1);
插入类别（category_id，要求）值 (1, '1,2,3'), (2, '1,2,4,5,6'), (3, '1,2,4,5,6');
I've got 2 tables, I want to select entries from one table, where there are entries in the second table for a list of items.
for example:
entry
id=1 requirements=(1,2,3)
id=2 requirements=(1,3,5)
submission
id=1 entry=1 requirement=1
id=2 entry=2 requirement=2
id=3 entry=3 requirement=3
Would select entry id=1, but not entry id=2 (so WHERE IN doesn't do the job)
*edit actual datasets:
INSERT INTO submission (entry_id, requirement_id, submission_id) VALUES
(17, 1, 1),
(43, 1, 2),
(57, 0, 3),
(57, 0, 4),
(1, 1, 5),
(26, 1, 6),
(40, 1, 7),
(40, 1, 8),
(40, 1, 9),
(40, 1, 10),
(85, 1, 11),
(94, 1, 12),
(114, 0, 13),
(32, 1, 14),
(34, 0, 15);
INSERT INTO entry (entry_id, category_id) VALUES
(1, 2),
(2, 1),
(3, 1),
(4, 1),
(5, 2),
(6, 1),
(7, 1),
(8, 1),
(9, 1),
(10, 1),
(11, 1),
(12, 1),
(13, 1),
(14, 1),
(15, 1);
INSERT INTO category (category_id, requirement) VALUES
(1, '1,2,3'),
(2, '1,2,4,5,6'),
(3, '1,2,4,5,6');
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查找表 1 中的所有行，其中表 2 中有 3 个匹配行：
我会为您的数据编写实际的查询，但我无法解读您的问题。
Find all rows in table 1 where there are 3 matching rows in table 2:
I'd write the actual query for your data but I can't decipher your question.