解析包含 3 个分隔符的字符串
我有一个二维数组,它是从字符串中分解出来的。一旦它爆炸,这就是输出:
---> 0 - 16~4~0.0~~~~false~~~~
---> 1 - 1000.0~21.75~L~1~2.0~2.0~L~2~
---> 2 -
---> 0 - 2~5~951.3~6.4~~~false~~~~
---> 1 - 1000.0~11.77~L~1~
---> 2 -
---> 0 - 3~6~1269.02~5.1~~~false~~~~
---> 1 - 5.0~213.66~L~1~4.9~2.56~L~2~4.6~19.5~L~3~
---> 2 - 5.1~53.44~B~1~5.4~8.48~B~2~5.5~15.53~B~3~
我想让它对于数组中的每个位置仅采用〜之前的第一个值。我不确定该怎么做。这是我到目前为止的代码:
$test = explode(":", $string);
foreach($test as &$value) $value = explode('|', $value);
以防万一您需要它,这是原始字符串输入:
1~1~828.32~12.5~~~假~~~~|1000.0~41.73~L~1~2.0~2.0~L~2~|:4~2~4.16~12.5~~~假~~ ~~|1000.0~21.75~L~1~2.0~2.0~L~2~|:9~3~0.16~24.0~~~假~~~~|1000.0~21.75~L~1~2.0~2.0~L ~2~|:16~4~0.0~~~~假~~~~|1000.0~21.75~L~1~2.0~2.0~L~2~|:2~5~951.3~6.4~~~假~ ~~~|1000.0~11.77~L~1~|:3~6~1269.02~5.1~~~假~~~~|5.0~213.66~L~1~4.9~2.56~L~2~4.6~19.5~ L~3~|5.1~53.44~B~1~5.4~8.48~B~2~5.5~15.53~B~3~:8~7~111.92~7.0~~~假~~~~|6.8~6.78~ L~1~6.6~148.39~L~2~6.4~3.7~L~3~|7.6~128.0'...
我希望输出为:
---> 0 - 16
---> 1 - 1000.0
---> 2 -
---> 0 - 2
---> 1 - 1000.0
---> 2 -
---> 0 - 3
---> 1 - 5.0
---> 2 - 5.1
I have a 2D array which I have exploded from a string. Once it has exploded this is what is output:
---> 0 - 16~4~0.0~~~~false~~~~
---> 1 - 1000.0~21.75~L~1~2.0~2.0~L~2~
---> 2 -
---> 0 - 2~5~951.3~6.4~~~false~~~~
---> 1 - 1000.0~11.77~L~1~
---> 2 -
---> 0 - 3~6~1269.02~5.1~~~false~~~~
---> 1 - 5.0~213.66~L~1~4.9~2.56~L~2~4.6~19.5~L~3~
---> 2 - 5.1~53.44~B~1~5.4~8.48~B~2~5.5~15.53~B~3~
I want to make it so that for each position in the array it only takes the first value before the ~. I am unsure how to do this. This is the code I have so far:
$test = explode(":", $string);
foreach($test as &$value) $value = explode('|', $value);
Just in case you need it this is the original string input:
1~1~828.32~12.5~~~false~~~~|1000.0~41.73~L~1~2.0~2.0~L~2~|:4~2~4.16~12.5~~~false~~~~|1000.0~21.75~L~1~2.0~2.0~L~2~|:9~3~0.16~24.0~~~false~~~~|1000.0~21.75~L~1~2.0~2.0~L~2~|:16~4~0.0~~~~false~~~~|1000.0~21.75~L~1~2.0~2.0~L~2~|:2~5~951.3~6.4~~~false~~~~|1000.0~11.77~L~1~|:3~6~1269.02~5.1~~~false~~~~|5.0~213.66~L~1~4.9~2.56~L~2~4.6~19.5~L~3~|5.1~53.44~B~1~5.4~8.48~B~2~5.5~15.53~B~3~:8~7~111.92~7.0~~~false~~~~|6.8~6.78~L~1~6.6~148.39~L~2~6.4~3.7~L~3~|7.6~128.0'...
I would like the output to be:
---> 0 - 16
---> 1 - 1000.0
---> 2 -
---> 0 - 2
---> 1 - 1000.0
---> 2 -
---> 0 - 3
---> 1 - 5.0
---> 2 - 5.1
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如果我理解正确,您想要获取该数组的每个元素并修剪第一个 ~ 字符之后的所有内容。基于您的代码:
我添加的只是一个内部 foreach 循环,它检查每个值并删除 ~ 字符之后的字符串的其余部分。
最好的编码!
If I understand correctly, you want to take each element of this array and trim off everything after the first ~ character. Building on your code:
All I added was an inner foreach loop that inspects each value and removes the rest of the string after the ~ character.
Best of coding!
如果我理解你的问题,这应该可行:
执行完成后, $output 将包含所需的信息。您还可以编写递归函数或使用正则表达式,但这两种解决方案都会更复杂一些。
哈
If I understand your question, this should work:
After this is finished executing, $output will contain the desired information. You could also write a recursive function or use a regex, but both those solutions would be a bit more complex.
hth
如果您只想剪切字符串部分直到分隔符,请使用 strtok() 而不是explode()。
我不太明白你现在的例子。但它可能是:
If you only want to cut out a string part until a delimiter, then use strtok() instead of explode().
I don't quite get your current example. But it might be:
您可以按 ~ 分解每一行并获取第一个元素。
但我认为如果您只需要第一个元素,这可能会变得非常低效。正则表达式可能是另一种解决方案。像这样:
匹配
|
之后到第一个~
的每个字符串。这会在字符串的开头处中断,但您可以在其前面添加|
以进行正则表达式匹配。You could explode each line by ~ and take the first element.
But I think this could become quite inefficient if you only need the first element. A regular expression could be another solution. Like this:
Matching every string after a
|
up to the first~
. This breaks at the beginning of your string, but you could prepend that with a|
for the regex matching.