javascript正则表达式匹配

发布于 2024-10-16 12:50:27 字数 706 浏览 8 评论 0原文

我需要根据空格作为分隔符来拆分如下所示的字符串。但引号内的任何空格都应保留。有两种情况需要工作，

情况 1

research library "not available" author:"Bernard Shaw"

到

research 
library 
"not available" 
author:"Bernard Shaw"

情况 2

research library "not available" author:Bernard

，

research 
library 
"not available" 
author:Bernard

我正在尝试使用 Javascript 和正则表达式来完成此操作。

var splitArray = query_string.match(/([^\s]*\"[^\"]+\")|\w+/g);

情况 1 按要求工作，但情况 2 产生如下结果，

research 
library 
"not available" 
author
Bernard

我需要这两种情况都与一个正则表达式一起使用。任何想法表示赞赏。

原文

I need to split a string like the one below, based on space as the delimiter. But any space within a quote should be preserved. There are two cases which needs to work

Case 1

research library "not available" author:"Bernard Shaw"

research 
library 
"not available" 
author:"Bernard Shaw"

Case 2

research library "not available" author:Bernard

research 
library 
"not available" 
author:Bernard

I am trying to do this with Javascript and regular expression.

var splitArray = query_string.match(/([^\s]*\"[^\"]+\")|\w+/g);

Case 1 works as required but Case 2 produces the result as below

research 
library 
"not available" 
author
Bernard

I need both the cases to work with one Regex. Any ideas appreciated.

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海未深 2024-10-23 12:50:27

[^"\s]+(?:"[^"]+")?|"[^"]+"

说明：

[^"\s]+       # One or more non-space/non-quote characters
(?:"[^"]+")?  # optionally followed by a quoted string
|             # or
"[^"]+"       # just a quoted string.

假设带引号的字符串中没有转义引号。

[^"\s]+(?:"[^"]+")?|"[^"]+"

Explanation:

[^"\s]+       # One or more non-space/non-quote characters
(?:"[^"]+")?  # optionally followed by a quoted string
|             # or
"[^"]+"       # just a quoted string.

Assuming that there are no escaped quotes within quoted strings.

回复收藏 0 原文

此刻的回忆 2024-10-23 12:50:27

([^\s]*\"[^\"]+\")|\w+:?

我在这里测试了这个正则表达式： rubular

更新：
您可能需要添加更多标点符号，例如 ; , . ? !
例如研究图书馆！ “不可用”作者：“萧伯纳”测试1，测试2；测试2！

([^\s]*\"[^\"]+\")|\w+[:;\.,\?!]?

([^\s]*\"[^\"]+\")|\w+:?

I've tested this regex here: rubular

update:
you may want to include some more punctuation marks like ; , . ? !
e.g. research library! "not available" author:"Bernard Shaw" test1, test2; test2!