在 Matlab 中访问矩阵
假设用户输入数据如下。我定义我的矩阵是成本。我创建的矩阵是 3 x 3 矩阵。所以矩阵应该这样形成：
cost = [c11 c12 c13
c21 c22 c23
c31 c32 c33]
因为我想显示行集，所以我这样做：
c1 = cost(1,:); % it will become c1 = c11 c12 c13
c2 = cost(2,:); % it will become c2 = c21 c22 c23
c3 = cost(3,:); % it will become c3 = c31 c32 c33
然后我想要矩阵中的值。我就是这样做的。
c11 = cost(1,1);
c12 = cost(1,2);
c13 = cost(1,3);
c21 = cost(2,1);
c22 = cost(2,2);
c23 = cost(2,3);
c31 = cost(3,1);
c32 = cost(3,2);
c33 = cost(3,3);
这就是我想用于此类矩阵的方程。
lambda =
((8*c13*c23*c33*Pdt)+(4*c12*c23*c33)+(4*c13*c22*c33)+(4*c13*c23*c32)) ./ (4*c23*c33)+(4*c13*c33)+(4*c13*c23));
所以我的问题是，如果我想制作 4 x 3 矩阵，它会生成一个像这样的矩阵：
cost = [c11 c12 c13
c21 c22 c23
c31 c32 c33
c41 c42 c43]
我想用于这个矩阵（4 x 3）的方程是完全不同的。那我要怎么做呢？我需要使用 if else 语句吗？或者做一会儿？谁能帮我解决这个问题吗？任何人都可以创建代码吗？
Assume user input data as below. I define my matrix is cost. The matrix i created is 3 by 3 matrix. So the matrix should form like this:
cost = [c11 c12 c13
c21 c22 c23
c31 c32 c33]
Since i want to display set of row, i do it like this :
c1 = cost(1,:); % it will become c1 = c11 c12 c13
c2 = cost(2,:); % it will become c2 = c21 c22 c23
c3 = cost(3,:); % it will become c3 = c31 c32 c33
Then i want the value in the matrix. I do it like this.
c11 = cost(1,1);
c12 = cost(1,2);
c13 = cost(1,3);
c21 = cost(2,1);
c22 = cost(2,2);
c23 = cost(2,3);
c31 = cost(3,1);
c32 = cost(3,2);
c33 = cost(3,3);
So this is the equation that i want to use for this type of matrix.
lambda =
((8*c13*c23*c33*Pdt)+(4*c12*c23*c33)+(4*c13*c22*c33)+(4*c13*c23*c32)) ./ (4*c23*c33)+(4*c13*c33)+(4*c13*c23));
So my problem is, if i want to make 4 by 3 matrix, and it would generate a matrix like this:
cost = [c11 c12 c13
c21 c22 c23
c31 c32 c33
c41 c42 c43]
The equation that i want to use for this matrix(4 by 3) is quite different. So how im gonna do it? Do i need to use if else statement? or do while? Can anyone help me solve this? Can anyone create the code?
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
为什么要显式创建变量 c11、c12、...？当然，像这样访问方程中的矩阵会更容易：
对于你的问题，是的，只需使用一个简单的 if 语句，如下所示：
Why do you explicitly create the variables c11, c12, ...? Surely it would be easier to just access the matrix in your equation like this:
For your question, yes, just use a simple if statment, like this: