元素“Root”的命名空间必须来自模式命名空间“http://www.w3.org/2001/XMLSchema”？

发布于 2024-10-16 09:02:27 字数 1752 浏览 1 评论 0 原文

我有一个 xml 文档：

<?xml version="1.0" encoding="utf-8"?>
<Root>
  <Child name="MyType" compareMode="EQ"></Child>
</Root>

我想在以下 xsd 的帮助下验证此 xml：

<?xml version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="Root">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="Child">
          <xs:complexType>
            <xs:attribute name="name" type="xs:string" use="required" />
            <xs:attribute name="compareMode" type="xs:string" use="required" />
          </xs:complexType>
        </xs:element>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>

当我尝试验证它时，我收到以下错误：

Exception in thread "main" org.xml.sax.SAXException: Validation failed against correct.xml. ErrorMessage:s4s-elt-schema-ns: The namespace of element 'Root' must be from the schema namespace, 'http://www.w3.org/2001/XMLSchema'.

我的问题是为什么 Root 必须位于模式的命名空间？难道是我验证xml文档不正确？

公共同步布尔 isValid(String xmlFragment, File xmlSchema) 抛出 SAXException、IOException{

// 1. 查找 W3C XML Schema 语言的工厂

SchemaFactory 工厂 = 
    SchemaFactory.newInstance(“http://www.w3.org/2001/XMLSchema”);

// 2. 编译架构。 

模式模式=factory.newSchema(xmlSchema);

// 3. 从模式中获取验证器。
验证器 validator = schema.newValidator();

// 4. 解析要检查的文档。
源源 = new StreamSource(new ByteArrayInputStream(xmlFragment.getBytes()));

// 5.检查文档    
    验证器.validate(源);        
    返回真；
}

原文

I have an xml document:

<?xml version="1.0" encoding="utf-8"?>
<Root>
  <Child name="MyType" compareMode="EQ"></Child>
</Root>

And I would like to validate this xml with help of the following xsd:

<?xml version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="Root">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="Child">
          <xs:complexType>
            <xs:attribute name="name" type="xs:string" use="required" />
            <xs:attribute name="compareMode" type="xs:string" use="required" />
          </xs:complexType>
        </xs:element>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>

When I try to validate it I receive the following error:

Exception in thread "main" org.xml.sax.SAXException: Validation failed against correct.xml. ErrorMessage:s4s-elt-schema-ns: The namespace of element 'Root' must be from the schema namespace, 'http://www.w3.org/2001/XMLSchema'.

My question is why Root has to be in the namespace of schema? Could that be that I validate the xml document not correctly?

public synchronized boolean isValid(String xmlFragment, File xmlSchema) throws SAXException, IOException{

// 1. Lookup a factory for the W3C XML Schema language

SchemaFactory factory = 
    SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

// 2. Compile the schema. 

Schema schema = factory.newSchema(xmlSchema);

// 3. Get a validator from the schema.
Validator validator = schema.newValidator();

// 4. Parse the document you want to check.
Source source = new StreamSource(new ByteArrayInputStream(xmlFragment.getBytes()));

// 5. Check the document    
    validator.validate(source);        
    return true;
}