如何使用 YQL 组合多个剩余查询？

发布于 2024-10-16 07:10:01 字数 328 浏览 5 评论 0原文

例如，我想将多个查询剩余查询组合在一起。现在，我一次使用不同的 URL 执行以下代码。我认为在我的例子中最终提出 10 个链接的一个请求会更快。任何帮助表示赞赏。

use 'http://javarants.com/yql/javascript.xml'as j; select * from j where code='response.object = y.rest("http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/").followRedirects(false).get().headers.location;'

原文

For example I would like to combine multiple queries rest queries together. Right now I do the following code with different URLs one at a time. I think it would be faster to ultimately make one request for 10 links in my case. Any help is appreciated.

use 'http://javarants.com/yql/javascript.xml'as j; select * from j where code='response.object = y.rest("http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/").followRedirects(false).get().headers.location;'

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冰雪之触 2024-10-23 07:10:01

一种可能是为此构建您自己的 YQL 表，然后该表在 ... 块中执行您需要的 javascript。

我想到的另一个替代方案是 query.multi YQL 表。

不确定这是否符合您的要求，但您可以尝试一下。不要更改尾部引号 (")，它需要直接保留在最后一个分号之后（这是一个我刚刚挣扎了几分钟的错误）。

USE 'http://javarants.com/yql/javascript.xml' AS j; 

SELECT * FROM query.multi WHERE queries="
select * from j where code='response.object = y.rest(\\'http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/\\').followRedirects(false).get().headers';
select * from j where code='response.object = y.rest(\\'http://stackoverflow.com/feeds/question/4917144\\').followRedirects(false).get().headers';"

One possibility would be to build your own YQL table for this, which then executes the javascript you need in an <execute>...</execute> block.

The other alternative that comes to mind is the query.multi YQL table.

Not sure that does what you want it do to but you can give it a try. Don't change the trailing quotation mark ("), it needs to stay directly after the last semicolon (this was a mistake that I just struggled with for some minutes).

USE 'http://javarants.com/yql/javascript.xml' AS j; 

SELECT * FROM query.multi WHERE queries="
select * from j where code='response.object = y.rest(\\'http://feedproxy.google.com/~r/Techcrunch/~3/P%5FqWQXyAPU/\\').followRedirects(false).get().headers';
select * from j where code='response.object = y.rest(\\'http://stackoverflow.com/feeds/question/4917144\\').followRedirects(false).get().headers';"

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