java.sql.SQLIntegrityConstraintViolationException
我在运行保存插入/更新命令时收到此错误:
SEVERE: null
java.sql.SQLIntegrityConstraintViolationException: The statement was aborted because it would have caused a duplicate key value in a unique or primary key constraint or unique index identified by 'SQL110207185137350' defined on 'EMPLOYEE'.
null, Boris Wilkins
如果有人能找出发生此错误的原因,那就太好了。
这是代码:
/////////////////////////////////////////////
/// UPDATE methods
/** Saves an existing pkg in the database */
public void save(Employee pkg) throws DataException {
Connection conn = null;
try {
conn = ConnectionPool.getInstance().get();
save(pkg, conn);
conn.commit();
} catch (Exception e) {
try {
conn.rollback();
} catch (SQLException ex) {
throw new DataException("We're currently upgrading our site to serve you better.", e);
}
throw new DataException("Problem saving the Employee", e);
} finally {
ConnectionPool.getInstance().release(conn);
}//update
}
/** Internal method to update a pkg in the database */
void save(Employee emp, Connection conn) {
// update the cache
Cache.getInstance().put(emp.getId(), emp);
// if not dirty, return
if (!emp.isDirty()) {
return;
}
// call either update() or insert()
if (emp.isObjectAlreadyInDB()) {
update(emp, conn);
} else {
insert(emp, conn);
}
}//save
/** Saves an existing pkg to the database */
//NEED HELP WITH EXECUTE STATEMENT!!!
private void update(Employee pkg, Connection conn) {
try {
// run the update SQL
PreparedStatement pstmt = conn.prepareStatement("UPDATE Employee SET id=?, name1=?, username1=?, password=?, type=? WHERE id=?");
pstmt.setString(1, pkg.getId());
pstmt.setString(2, pkg.getName1());
pstmt.setString(3, pkg.getUserName1());
pstmt.setString(4, pkg.getPassword());
pstmt.setString(5, pkg.getType());
pstmt.setString(6, pkg.getId());
pstmt.executeUpdate();
pstmt.close();
// update the dirty variable
pkg.setDirty(false);
} catch (SQLException ex) {
Logger.getLogger(EmployeeDAO.class.getName()).log(Level.SEVERE, null, ex);
}
}
/** Inserts a new pkg into the database */
private void insert(Employee pkg, Connection conn) {
try {
// run the insert SQL
PreparedStatement pstmt = conn.prepareStatement("INSERT into Employee (id, name1, username1, password, type) values(?, ?, ?, ?, ?)");
pstmt.setString(1, pkg.getId());
pstmt.setString(2, pkg.getName1());
pstmt.setString(3, pkg.getUserName1());
pstmt.setString(4, pkg.getPassword());
pstmt.setString(5, pkg.getType());
// update the dirty variable
pstmt.execute();
pstmt.close();
pkg.setDirty(false);
} catch (SQLException ex) {
Logger.getLogger(EmployeeDAO.class.getName()).log(Level.SEVERE, null, ex);
}
}
alreadyInDB 的代码:
/** Returns whether the object is in the DB or not */
boolean isObjectAlreadyInDB() {
return objectAlreadyInDB;
}//isObjectAlreadyInDB
/**
* Sets whether the object is already in the DB. This method
* is called ONLY from the DAO responsible for this object.
*/
void setObjectAlreadyInDB(boolean objectAlreadyInDB) {
this.objectAlreadyInDB = objectAlreadyInDB;
}//setObjectAlreadyInDB
I am getting this error when running a save insert/update command:
SEVERE: null
java.sql.SQLIntegrityConstraintViolationException: The statement was aborted because it would have caused a duplicate key value in a unique or primary key constraint or unique index identified by 'SQL110207185137350' defined on 'EMPLOYEE'.
null, Boris Wilkins
If anyone can spot why this error is happening it would be great.
here is the code:
/////////////////////////////////////////////
/// UPDATE methods
/** Saves an existing pkg in the database */
public void save(Employee pkg) throws DataException {
Connection conn = null;
try {
conn = ConnectionPool.getInstance().get();
save(pkg, conn);
conn.commit();
} catch (Exception e) {
try {
conn.rollback();
} catch (SQLException ex) {
throw new DataException("We're currently upgrading our site to serve you better.", e);
}
throw new DataException("Problem saving the Employee", e);
} finally {
ConnectionPool.getInstance().release(conn);
}//update
}
/** Internal method to update a pkg in the database */
void save(Employee emp, Connection conn) {
// update the cache
Cache.getInstance().put(emp.getId(), emp);
// if not dirty, return
if (!emp.isDirty()) {
return;
}
// call either update() or insert()
if (emp.isObjectAlreadyInDB()) {
update(emp, conn);
} else {
insert(emp, conn);
}
}//save
/** Saves an existing pkg to the database */
//NEED HELP WITH EXECUTE STATEMENT!!!
private void update(Employee pkg, Connection conn) {
try {
// run the update SQL
PreparedStatement pstmt = conn.prepareStatement("UPDATE Employee SET id=?, name1=?, username1=?, password=?, type=? WHERE id=?");
pstmt.setString(1, pkg.getId());
pstmt.setString(2, pkg.getName1());
pstmt.setString(3, pkg.getUserName1());
pstmt.setString(4, pkg.getPassword());
pstmt.setString(5, pkg.getType());
pstmt.setString(6, pkg.getId());
pstmt.executeUpdate();
pstmt.close();
// update the dirty variable
pkg.setDirty(false);
} catch (SQLException ex) {
Logger.getLogger(EmployeeDAO.class.getName()).log(Level.SEVERE, null, ex);
}
}
/** Inserts a new pkg into the database */
private void insert(Employee pkg, Connection conn) {
try {
// run the insert SQL
PreparedStatement pstmt = conn.prepareStatement("INSERT into Employee (id, name1, username1, password, type) values(?, ?, ?, ?, ?)");
pstmt.setString(1, pkg.getId());
pstmt.setString(2, pkg.getName1());
pstmt.setString(3, pkg.getUserName1());
pstmt.setString(4, pkg.getPassword());
pstmt.setString(5, pkg.getType());
// update the dirty variable
pstmt.execute();
pstmt.close();
pkg.setDirty(false);
} catch (SQLException ex) {
Logger.getLogger(EmployeeDAO.class.getName()).log(Level.SEVERE, null, ex);
}
}
Code for alreadyInDB:
/** Returns whether the object is in the DB or not */
boolean isObjectAlreadyInDB() {
return objectAlreadyInDB;
}//isObjectAlreadyInDB
/**
* Sets whether the object is already in the DB. This method
* is called ONLY from the DAO responsible for this object.
*/
void setObjectAlreadyInDB(boolean objectAlreadyInDB) {
this.objectAlreadyInDB = objectAlreadyInDB;
}//setObjectAlreadyInDB
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(2)
这条语句
emp.isObjectAlreadyInDB()
显然失败了,并且始终返回false
,导致每次运行代码时都会插入相同的员工,从而违反了主键或您在该数据库表中设置的唯一约束。This statement
emp.isObjectAlreadyInDB()
is obviously failing and returningfalse
all the time, causing the same employee to be inserted everytime you run the code, thus violating the primary key or unique constraint you set up in that database table.我正在使用测试器类,并且意外地创建了一个与数据库中已有对象具有相同 id 的对象。
I am using a tester class and i was accidentally creating an object with the same id as an object that was already in the DB.