如果模型中的验证出现错误,则禁用按钮
您好,我对模型类中的错误进行验证。
public class CurrentUser:IDataErrorInfo, INotifyPropertyChanged
{
//...
private string _validationResult;
private string _nick;
public string Nick
{
get { return _nick; }
set
{
_nick = value;
NotifyPropertyChanged("Nick");
}
}
public string ValidationResult
{
get { return _validationResult; }
private set
{
_validationResult = value;
NotifyPropertyChanged("ValidationResult");
}
}
#region Implementation of INotifyPropertyChanged
public event PropertyChangedEventHandler PropertyChanged;
private void NotifyPropertyChanged(String info)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(info));
}
}
#endregion
#region Implementation of IDataErrorInfo
private string NickValid()
{
if (string.IsNullOrEmpty(Nick))
{
return NickNull;
}
if (Regex.IsMatch(Nick, "[^a-zA-Z0-9-_.]"))
{
return NickInvalidCharacters;
}
return string.Empty;
}
public string Error
{
get { throw new NotImplementedException(); }
}
public string this[string propertyName]
{
get
{
ValidationResult = string.Empty;
switch (propertyName)
{
case "Nick":
ValidationResult = NickValid();
break;
default:
break;
}
return ValidationResult;
}
}
#endregion
}
我在视图模型中使用这个模型类,并将模型类的 Nick 属性绑定到组合框控件的 Text 属性。
此外,我还在视图中的按钮单击事件上绑定了视图模型类中的 LogOn 方法。如果模型类中的验证有错误,我想要禁用按钮:
查看模型:
[Export(typeof(ILogOnViewModel))]
[PartCreationPolicy(CreationPolicy.NonShared)]
public class LogOnViewModel : Screen, ILogOnViewModel,
IPartImportsSatisfiedNotification
{
public CurrentUser CurrentUser { get; set; }
public bool CanLogOn
{
get
{
return string.IsNullOrWhiteSpace(CurrentUser.ValidationResult);
}
}
//bind on button click event
public void LogOn()
{}
}
解决方案很简单,如果 CurrentUser(对象)属性中的验证有错误,则将 CanLogOn 属性设置为 false。
但我不知道如何通知模型类中的属性 CanLogOn 没有错误。我运行应用程序,按钮仍然处于禁用状态。
我需要在模型中实现这种行为:
public string ValidationResult
{
get { return _validationResult; }
private set
{
_validationResult = value;
NotifyPropertyChanged("ValidationResult");
//notify property CanLogOn in view model class
}
}
有什么建议吗?感谢。
Hi I make validation on error in my model class.
public class CurrentUser:IDataErrorInfo, INotifyPropertyChanged
{
//...
private string _validationResult;
private string _nick;
public string Nick
{
get { return _nick; }
set
{
_nick = value;
NotifyPropertyChanged("Nick");
}
}
public string ValidationResult
{
get { return _validationResult; }
private set
{
_validationResult = value;
NotifyPropertyChanged("ValidationResult");
}
}
#region Implementation of INotifyPropertyChanged
public event PropertyChangedEventHandler PropertyChanged;
private void NotifyPropertyChanged(String info)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(info));
}
}
#endregion
#region Implementation of IDataErrorInfo
private string NickValid()
{
if (string.IsNullOrEmpty(Nick))
{
return NickNull;
}
if (Regex.IsMatch(Nick, "[^a-zA-Z0-9-_.]"))
{
return NickInvalidCharacters;
}
return string.Empty;
}
public string Error
{
get { throw new NotImplementedException(); }
}
public string this[string propertyName]
{
get
{
ValidationResult = string.Empty;
switch (propertyName)
{
case "Nick":
ValidationResult = NickValid();
break;
default:
break;
}
return ValidationResult;
}
}
#endregion
}
This model class I use in view model and I bind Nick property of model class to the Text property of comboBox control.
Also I bind method LogOn from view model class on button click event in view. I would like disabale button if validation in model class has error:
View model:
[Export(typeof(ILogOnViewModel))]
[PartCreationPolicy(CreationPolicy.NonShared)]
public class LogOnViewModel : Screen, ILogOnViewModel,
IPartImportsSatisfiedNotification
{
public CurrentUser CurrentUser { get; set; }
public bool CanLogOn
{
get
{
return string.IsNullOrWhiteSpace(CurrentUser.ValidationResult);
}
}
//bind on button click event
public void LogOn()
{}
}
Solution is simple set CanLogOn property on false if validation in CurrentUser (object) property has error.
But I don’t how notify property CanLogOn that in model class is not error. I run app and button is still disabled.
I need achive this behavior in model:
public string ValidationResult
{
get { return _validationResult; }
private set
{
_validationResult = value;
NotifyPropertyChanged("ValidationResult");
//notify property CanLogOn in view model class
}
}
Any advice? Thank.
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
将事件处理程序附加到视图模型中用户的
PropertyChanged
事件:添加如果
ValidationResult
更改则发送通知:注意:如果您的引用
CurrentUser
被覆盖,您需要将事件处理程序添加到新对象。您可以通过将附件代码放置在CurrentUser
的 setter 中来完成此操作。Attach an event handler to the
PropertyChanged
event of the user in your viewmodel:Add send a notification if the
ValidationResult
changes:Note: If your reference
CurrentUser
is overwritten you need to add the event handler to the new object. You could do this by placing the attachment code in the setter ofCurrentUser
.