大海捞针搜索非主要领域

发布于 2024-10-15 11:02:57 字数 584 浏览 2 评论 0原文

我希望有任何从两个不同字段搜索索引模型的选项。例如，有时按姓名搜索，有时按职业搜索。有人知道采取正确的方法吗？这是我当前的 search_indexes.py 文件：

class JobIndex(indexes.SearchIndex):
    text = indexes.CharField(document=True)
    name = indexes.CharField(model_attr='name')
    occupation = indexes.CharField(model_attr='occupation')

    def prepare(self, obj):
        self.prepared_data = super(JobIndex, self).prepare(obj)
        self.prepared_data['text'] = obj.name
        return self.prepared_data
    def get_queryset(self):
        return Job.objects.filter(status='open')
site.register(Job, JobIndex)

原文

I would like to have any option of searching an indexed model from two different fields. For example, sometimes search by name and other times search by occupation. Does someone know the right approach to take? This is my current search_indexes.py file:

class JobIndex(indexes.SearchIndex):
    text = indexes.CharField(document=True)
    name = indexes.CharField(model_attr='name')
    occupation = indexes.CharField(model_attr='occupation')

    def prepare(self, obj):
        self.prepared_data = super(JobIndex, self).prepare(obj)
        self.prepared_data['text'] = obj.name
        return self.prepared_data
    def get_queryset(self):
        return Job.objects.filter(status='open')
site.register(Job, JobIndex)

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遮了一弯 2024-10-22 11:02:57

正确的方法是使用带有过滤器的 SearchQuerySet： http://docs.haystacksearch.org/dev/ searchqueryset_api.html

在你的情况下，它看起来像：

from haystack.query import SearchQuerySet

sqs = SearchQuerySet()

# Find people named Bob
sqs.filter(name="Bob")
# Find people who are developers
sqs.filter(occupation="developer")
# Or chain searches: Find developers named Bob
sqs.filter(occupation="developer").filter(name="Bob")

The right approach is to use a SearchQuerySet with filters: http://docs.haystacksearch.org/dev/searchqueryset_api.html

In your case, it'd look something like:

from haystack.query import SearchQuerySet

sqs = SearchQuerySet()

# Find people named Bob
sqs.filter(name="Bob")
# Find people who are developers
sqs.filter(occupation="developer")
# Or chain searches: Find developers named Bob
sqs.filter(occupation="developer").filter(name="Bob")

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