显示其他网页的新闻

Question

我想将另一个网页上的新闻显示到我的网页上，但我无法找出最佳方法。

另一个网页上的新闻显示在 div 类中，如下所示

<div class="news-container"> 
<div class="news-list"><a href="news/1/" title="abcd"><img src="abcd.jpg" /><strong>abcd</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/1/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div> 
<div class="news-list"><a href="news/2/" title="efgh"><img src="efgh.jpg" /><strong>efgh</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/3/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div> 
<div class="news-list"><a href="news/3/" title="ijkl"><img src="ijkl.jpg" /><strong>ijkl</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/3/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div> 
<div class="news-list"><a href="news/4/" title="mnop"><img src="mnop.jpg" /><strong>mnop</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/4/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div>

我希望能够循环浏览新闻并将其显示在我自己的页面上，并根据我们自己的网站布局重新排列。

<div class="other-news"> 
<div class="news-list"><strong>abcd</strong>
    <p>What you see is what you get. <a href="news/1/" title="abcd"><img src="abcd.jpg" /></a></p> 
</div> 
<div class="news-list"><strong>efgh</strong>
    <p>What you see is what you get. <a href="news/3/" title="abcd"><img src="efgh.jpg" /></a> </p> 
</div> 
<div class="news-list"><strong>ijkl</strong>
    <p>What you see is what you get. <a href="news/3/" title="abcd"><img src="ijkl.jpg" /></a> </p> 
</div> 
<div class="news-list"><strong>mnop</strong>
    <p>What you see is what you get. <a href="news/4/" title="abcd"><img src="mnop.jpg" /></a> </p>
</div>

我们非常欢迎所有建议。

// 尼堡

Answer 1

您需要查看 PHP cURL 或 file_get_contents（安全问题）或查看 PHP HTML DOM 解析器。

还要看看你所做的事情是否合法？ （如果他们想让你拥有内容，他们通常会提供 API）