“调用未定义的函数”调用类方法时出错

发布于 2024-10-15 01:08:09 字数 1169 浏览 0 评论 0原文

这是错误致命错误：调用未定义的函数分配(
这是代码，正如你所看到的，我显然已经定义了该函数，所以为什么它不起作用

class shades {
    function create($name, $shades, $slug, $shortDesc, $longDesc, $position){
        $name = sanitize_paranoid_string($name);
        $slug = slug($name);
        $shortDesc = sanitize_sql_string($shortDesc);
        $longDesc = sanitize_sql_string($longDesc);
        $query = mysql_query("INSERT INTO products (type, name, slug, shortDesc, htmlDesc, position)VALUES('shades','$name','$slug','$shortDesc','$longDesc','$position')")or die(mysql_error());  
        $ID = mysql_insert_id();
        assign($shades, $ID);
        if($query) {return true;}
        else {return false;};
    }
    function delassign($toID){
        mysql_query("DELETE FROM assign WHERE type='shades' AND toID='$toID'")or die(mysql_error());    
    }
    function assign($shades, $toID)
    {
        foreach($shades as $shade)
        {
            $result = mysql_query("INSERT INTO assign(type, typeID, toID)VALUES('shades','$shade','$toID')")or die(mysql_error());
            if($result){echo "Added!";}
            else{echo"Not Added!";}
        };  
    }
}

原文

this is the error Fatal error: Call to undefined function assign(
this is the code, as you can see i obviously have defined the function so why is it not working

class shades {
    function create($name, $shades, $slug, $shortDesc, $longDesc, $position){
        $name = sanitize_paranoid_string($name);
        $slug = slug($name);
        $shortDesc = sanitize_sql_string($shortDesc);
        $longDesc = sanitize_sql_string($longDesc);
        $query = mysql_query("INSERT INTO products (type, name, slug, shortDesc, htmlDesc, position)VALUES('shades','$name','$slug','$shortDesc','$longDesc','$position')")or die(mysql_error());  
        $ID = mysql_insert_id();
        assign($shades, $ID);
        if($query) {return true;}
        else {return false;};
    }
    function delassign($toID){
        mysql_query("DELETE FROM assign WHERE type='shades' AND toID='$toID'")or die(mysql_error());    
    }
    function assign($shades, $toID)
    {
        foreach($shades as $shade)
        {
            $result = mysql_query("INSERT INTO assign(type, typeID, toID)VALUES('shades','$shade','$toID')")or die(mysql_error());
            if($result){echo "Added!";}
            else{echo"Not Added!";}
        };  
    }
}

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

赠意 2024-10-22 01:08:09

您没有名为 assign() 的函数，而是具有此名称的方法。 PHP 不是 Java，在 PHP 中你必须明确，如果你想调用函数

assign()

或方法

$object->assign()

，在你的情况下，对函数的调用驻留在另一个方法中。 $this 始终引用其中存在方法的对象本身。

$this->assign()

You dont have a function named assign(), but a method with this name. PHP is not Java and in PHP you have to make clear, if you want to call a function

assign()

or a method

$object->assign()

In your case the call to the function resides inside another method. $this always refers to the object, in which a method exists, itself.

$this->assign()

回复收藏 0 原文

九厘米的零° 2024-10-22 01:08:09

您需要像这样调用函数，

$this->assign()

而不仅仅是 assign()

you need to call the function like this

$this->assign()

instead of just assign()

回复收藏 0 原文

萌化 2024-10-22 01:08:09

伙计们，

我今天在测试一个简单的脚本时偶然发现了这个错误。不过，我没有使用“类”函数，所以对它持保留态度。
我在函数定义之前调用函数 &声明...类似这样的东西

      try{
             foo();
         }
       catch (exception $e)
           {
            echo "$e->getMessage()";
           }

       function foo(){
                       echo "blah blah blah";
                     }

，所以 php 向我抛出错误“调用未定义的函数”。

这看起来有点经典的编程错误，但可能会帮助需要线索的人。

Mates,

I stumbled upon this error today while testing a simple script. I am not using "class" function though so it take it with grain of salt.
I was calling function before its definition & declaration ...something like this

      try{
             foo();
         }
       catch (exception $e)
           {
            echo "$e->getMessage()";
           }

       function foo(){
                       echo "blah blah blah";
                     }

so php was throwing me error "call to undefined function ".

This kinda seem classic programming error but may help someone in need of clue.

回复收藏 0 原文