Mongoid，无法对嵌入文档进行版本控制吗？

Question

我在这里缺少什么？

我这里有一个相对简单的结构：

Class Content 
  include Mongoid::Document 
   include Mongoid::Timestamps 
   include Mongoid::Paranoia 
    field :title 
    embeds_many :localized_contents 
 end 

 Class LocalizedContent 
   include Mongoid::Document 
   include Mongoid::Timestamps 
   include Mongoid::Paranoia 
   include Mongoid::Versioning 
    field :locale 
    field :content 
    embedded_in :content, :inverse_of => :localized_contents 
 end 

如果我这样做：

 test = LocalizeContent.new(:locale => 'en', :content => 'blah') 
 test.save 

 => ok, version = 1 

 test.content = 'blah2' 
 test.save 

 => ok, version = 2, versions.count = 1, etc. 

一切都好

现在如果我通过内容执行此操作，它不起作用

 test = Content.first.localised_contents.build(:locale => 'en', :content => 'blah') 
 test.save 

 => ok, version = 1 

 test = Content.first.localized_contents.first 
 test.content = 'blah2' 
 test.save 

 => KO, version = 1, versions.count = 0, but 
 Content.first.localized_contents.first.content == 'blah2' 

我在这里做错了什么？！？

谢谢， 亚历克斯

Answer 1

遗憾的是，Mongoid::Versioning 和 Mongoid::Paranoia 目前无法处理嵌入文档。

Answer 2

我正在使用 mongo (1.9.1) & mongoid (2.7.1) 并且似乎有一种方法可以强制嵌入文档进行版本控制。

这有点 hackey - 但基本上我们更改嵌套文档，然后更新父文档的“previous_update”字段。

params = { 'env_name' => 'changeme-qa', 'machine' => {'_id' =>"51f85846f0e1801113000003", 'status' => "described#{version}" }}

env = Environment.find_with_name(params['env_name'])
result = env.machines.where(:_id => params['machine']['_id'])
machine = (result.exists?) ?  machine = result.first : nil

if machine.nil?
  raise 'failed to find machine'
else
  if machine.update_attributes(params['machine'])
    env.reload 
    # here's the magic, since we cause a change in the parent (environment) record,
    # the child records get versioned
    env['previous_update'] = env['updated_at']
    env.save
  else
    raise 'failed to save'
  end
end