反射说接口方法在实现的类型中是虚拟的，但它们不是吗？

发布于 2024-10-14 18:27:52 字数 1003 浏览 3 评论 0原文

我在单元测试中有以下代码

    public bool TestMethodsOf<T, I>()
  {
   var impl = typeof(T);
   var valid = true;

   foreach (var iface in impl.GetInterfaces().Where(i => typeof(I).IsAssignableFrom(i)))
   {

    var members = iface.GetMethods();

    foreach (var member in members)
    {
     Trace.Write("Checking if method " + iface.Name + "." + member.Name + " is virtual...");
     var implMember = impl.GetMethod(member.Name, member.GetParameters().Select(c => c.ParameterType).ToArray());
     if (!implMember.IsVirtual)
     {
      Trace.WriteLine(string.Format("FAILED"));
      valid = false;
      continue;
     }

     Trace.WriteLine(string.Format("OK"));
    }
   }
   return valid;
  }

，

Assert.IsTrue(TestMethodsOf<MyView, IMyView>());

我想确保接口中的所有方法都声明为虚拟方法。原因是因为我正在应用 spring.net 方面，并且它仅适用于虚拟方法。

我遇到的问题是 implMember.IsVirtual 始终为 true，即使它们没有在声明类型中如此声明。

我的 TestMethodsOf 逻辑有什么问题？

干杯

原文

I have the following code in an unit test

    public bool TestMethodsOf<T, I>()
  {
   var impl = typeof(T);
   var valid = true;

   foreach (var iface in impl.GetInterfaces().Where(i => typeof(I).IsAssignableFrom(i)))
   {

    var members = iface.GetMethods();

    foreach (var member in members)
    {
     Trace.Write("Checking if method " + iface.Name + "." + member.Name + " is virtual...");
     var implMember = impl.GetMethod(member.Name, member.GetParameters().Select(c => c.ParameterType).ToArray());
     if (!implMember.IsVirtual)
     {
      Trace.WriteLine(string.Format("FAILED"));
      valid = false;
      continue;
     }

     Trace.WriteLine(string.Format("OK"));
    }
   }
   return valid;
  }

which I call by

Assert.IsTrue(TestMethodsOf<MyView, IMyView>());

I want to ensure that all the methods from the interface are declared as virtual. The reason is because I'm applying a spring.net aspect and it will only apply to virtual methods.

The problem I'm having is that implMember.IsVirtual is always true, even when they are not declared as so in the declaring type.

What is wrong with my TestMethodsOf logic?

Cheers

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冧九 2024-10-21 18:27:52

所有在接口中声明的方法都被标记为virtualabstract，所有在类中实现接口方法的方法都被标记为virtualfinal，因此CLR知道它不能只是直接调用它们 - 它必须在运行时进行 vtable 查找才能调用正确的实现。接口实现仍然是虚拟的，但您不能覆盖它们，因为它们是最终的。

例如，以下 C# 定义：

public interface IInterface {
    void Method();
}

public class Class : IInterface {
    public void Method() {}
}

编译为以下 IL：

.class public interface abstract IInterface {
    .method public abstract virtual instance void Method() {}
}

.class public Class extends [mscorlib]System.Object implements IInterface {
    .method public specialname rtspecialname instance void .ctor() {}
    .method public virtual final instance void Method() {}
}

All methods declared in an interface are marked as virtual abstract, and all methods that implement interface methods in classes are marked as virtual final, so the CLR knows it can't just call them directly - it has to do vtable lookups at runtime to call the right implementation. The interface implementations are still virtual, but you can't override them as they're final.

As an example, the following C# definition:

public interface IInterface {
    void Method();
}

public class Class : IInterface {
    public void Method() {}
}

compiles to the following IL:

.class public interface abstract IInterface {
    .method public abstract virtual instance void Method() {}
}

.class public Class extends [mscorlib]System.Object implements IInterface {
    .method public specialname rtspecialname instance void .ctor() {}
    .method public virtual final instance void Method() {}
}

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