如何检测用户是否取消选中复选框？

发布于 2024-10-14 17:01:54 字数 735 浏览 5 评论 0原文

形式如下：

    <form action="x.php" method="get" id="myForm">Subscribe:
<div id="radioButtonsWithAdds">
    <input type="radio" name="group1" value="one">One month 2,99$  
    <input type="radio" name="group1" value="two"> Two months   5,98$</div><br>
    <input type="checkbox" name="option1" value="withAdds" checked>  with adds
    <img src="next.png" border="0" alt="enviar" onclick="document.getElementById('myForm').submit();"> 
    </form>

是订阅的第一部分。在这里，用户可以选择一个月或两个月的订阅。

如果用户同意接收添加，选中复选框，就这样，他/她可以点击下一步按钮，就可以了。

但是，如果用户取消选中“添加”复选框，则 #radioButtonsWithAdds 的位置将显示一个 div，其中包含另一组具有不同价格的单选按钮。

如何在不点击任何提交按钮的情况下检测复选框是否已选中？

原文

The following form:

    <form action="x.php" method="get" id="myForm">Subscribe:
<div id="radioButtonsWithAdds">
    <input type="radio" name="group1" value="one">One month 2,99$  
    <input type="radio" name="group1" value="two"> Two months   5,98lt;/div><br>
    <input type="checkbox" name="option1" value="withAdds" checked>  with adds
    <img src="next.png" border="0" alt="enviar" onclick="document.getElementById('myForm').submit();"> 
    </form>

Is the first part of a subscription from. In here, the user may choose between one month or two months subscription.

If the user agrees to receive adds, leaves the checkbox checked, that will be all, he/she can hit the next button and it's ok.

But if the user unchecks the "with adds" checkbox, a div will show in the place of the #radioButtonsWithAdds one containing another set of radio buttons with different prices.

How can I detect that the checkbox ish without hitting any submit button?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

夜唯美灬不弃 2024-10-21 17:01:54

$('#yourcheckbox').change(function() {

   if ( ! this.checked) {
       // It is not checked, show your div...

   }

});

$('#yourcheckbox').change(function() {

   if ( ! this.checked) {
       // It is not checked, show your div...

   }

});

回复收藏 0 原文

空名 2024-10-21 17:01:54

你也可以这样做：

$('input[name=subscribe]').change(function() {
   if ($(this).is(':checked')) {
     // the user selected the checkbox
   } else {
     // the user de-selected the checkbox
   }
});

You could also do something like this:

$('input[name=subscribe]').change(function() {
   if ($(this).is(':checked')) {
     // the user selected the checkbox
   } else {
     // the user de-selected the checkbox
   }
});

回复收藏 0 原文

可是我不能没有你 2024-10-21 17:01:54

HTML

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <meta name="generator" content="test"/>
    <title></title>
  </head>
  <body>
    <form action="x.php" method="get" id="myForm" name="myForm">
      Subscribe:
      <div id="radioButtonsWithOutAdds" style="display:none;">
        <input type="radio" name="group1" value="one">One month 1,99$
        <input type="radio" name="group1" value="two"> Two months 2,98$
      </div>
      <div id="radioButtonsWithAdds">
        <input type="radio" name="group1" value="one">One month 2,99$
        <input type="radio" name="group1" value="two"> Two months 5,98$
      </div><br>
      <input type="checkbox" name="option1" value="withAdds" checked> with adds
      <img src="next.png" border="0" alt="enviar" onclick=
      "document.getElementById('myForm').submit();">
    </form>
  </body>
</html>

$(document).ready(function(){
    $("#myForm > input[type='checkbox']").click(function(){
        if(!$(this).is(':checked'))
        {
            $("#radioButtonsWithOutAdds").show();
            $("#radioButtonsWithAdds").hide();
        }
        else
        {
            $("#radioButtonsWithOutAdds").hide();
            $("#radioButtonsWithAdds").show();
        }
    })
})

这是一个简单的示例：
http://jsfiddle.net/efhHF/2/

HTML

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <meta name="generator" content="test"/>
    <title></title>
  </head>
  <body>
    <form action="x.php" method="get" id="myForm" name="myForm">
      Subscribe:
      <div id="radioButtonsWithOutAdds" style="display:none;">
        <input type="radio" name="group1" value="one">One month 1,99$
        <input type="radio" name="group1" value="two"> Two months 2,98$
      </div>
      <div id="radioButtonsWithAdds">
        <input type="radio" name="group1" value="one">One month 2,99$
        <input type="radio" name="group1" value="two"> Two months 5,98$
      </div><br>
      <input type="checkbox" name="option1" value="withAdds" checked> with adds
      <img src="next.png" border="0" alt="enviar" onclick=
      "document.getElementById('myForm').submit();">
    </form>
  </body>
</html>

$(document).ready(function(){
    $("#myForm > input[type='checkbox']").click(function(){
        if(!$(this).is(':checked'))
        {
            $("#radioButtonsWithOutAdds").show();
            $("#radioButtonsWithAdds").hide();
        }
        else
        {
            $("#radioButtonsWithOutAdds").hide();
            $("#radioButtonsWithAdds").show();
        }
    })
})

Here is a quick example:
http://jsfiddle.net/efhHF/2/

回复收藏 0 原文

不再见 2024-10-21 17:01:54

您需要绑定一个事件监听器并检查那里的状态。

$('#radioButtonsWithAdds').find('input:checkbox').bind('change', function() {
    if(this.checked) {
    }
    else {
         // the user unchecked the checkbox!
    }
});

You need to bind an event listener and check the state there.

$('#radioButtonsWithAdds').find('input:checkbox').bind('change', function() {
    if(this.checked) {
    }
    else {
         // the user unchecked the checkbox!
    }
});

回复收藏 0 原文

荒路情人 2024-10-21 17:01:54

尝试使用这个

          <TD width=550 align=left> 
                <input type="checkbox" name="adesao" value="sim" id="parte1" onClick="mostra()" /> Sim   
                <div id="sumula" style="display:none"> 
                    <input type="radio" name="conteudo_sumula" value="1" /> <small><i>1x</i></small> 
                    <input type="radio" name="conteudo_sumula" value="2" /> <small><i>2x</i></small> 
                    <input type="radio" name="conteudo_sumula" value="3" /> <small><i>3x</i></small> 
                </div> 
          </TD>

这是 JS 函数

function mostra(){
    if (document.getElementById("sumula").style.display != "none"){
        document.getElementById("sumula").style.display = "none";
    }else{
        document.getElementById("sumula").style.display = "block";
    }
}

Try to use this

          <TD width=550 align=left> 
                <input type="checkbox" name="adesao" value="sim" id="parte1" onClick="mostra()" /> Sim   
                <div id="sumula" style="display:none"> 
                    <input type="radio" name="conteudo_sumula" value="1" /> <small><i>1x</i></small> 
                    <input type="radio" name="conteudo_sumula" value="2" /> <small><i>2x</i></small> 
                    <input type="radio" name="conteudo_sumula" value="3" /> <small><i>3x</i></small> 
                </div> 
          </TD>

Here goes the JS function

function mostra(){
    if (document.getElementById("sumula").style.display != "none"){
        document.getElementById("sumula").style.display = "none";
    }else{
        document.getElementById("sumula").style.display = "block";
    }
}

回复收藏 0 原文

~没有更多了~