如何将 printStackTrace 存储到字符串中

Question

如何获取 e.printStackTrace() 并将其存储到 String 变量中？ 我想稍后在程序中使用由 e.printStackTrace() 生成的字符串。

我对 Java 还很陌生，所以我认为我对 StringWriter 不太熟悉 将是解决方案。或者如果您有任何其他想法请告诉我。谢谢

Answer 1

类似于

StringWriter errors = new StringWriter();
ex.printStackTrace(new PrintWriter(errors));
return errors.toString();

“应该是您所需要的”的东西。

相关文档：

• StringWriter
• PrintWriter
• Throwable

Answer 2

Guava 通过 Throwables.getStackTraceAsString(Throwable)：

Exception e = ...
String stackTrace = Throwables.getStackTraceAsString(e);

在内部，这会做什么@Zach L 建议。

Answer 3

您可以使用 Apache Commons 3 类 org.apache.commons.lang3.exception.ExceptionUtils 中的 ExceptionUtils.getStackTrace(Throwable t);。

http://commons.apache.org/proper/commons-lang/

ExceptionUtils.getStackTrace(Throwable t)

代码示例：

try {

  // your code here

} catch(Exception e) {
  String s = ExceptionUtils.getStackTrace(e);
}

Answer 4

您必须使用 getStackTrace () 方法而不是 printStackTrace()。这是一个很好的例子：

import java.io.*;

/**
* Simple utilities to return the stack trace of an
* exception as a String.
*/
public final class StackTraceUtil {

  public static String getStackTrace(Throwable aThrowable) {
    final Writer result = new StringWriter();
    final PrintWriter printWriter = new PrintWriter(result);
    aThrowable.printStackTrace(printWriter);
    return result.toString();
  }

  /**
  * Defines a custom format for the stack trace as String.
  */
  public static String getCustomStackTrace(Throwable aThrowable) {
    //add the class name and any message passed to constructor
    final StringBuilder result = new StringBuilder( "BOO-BOO: " );
    result.append(aThrowable.toString());
    final String NEW_LINE = System.getProperty("line.separator");
    result.append(NEW_LINE);

    //add each element of the stack trace
    for (StackTraceElement element : aThrowable.getStackTrace() ){
      result.append( element );
      result.append( NEW_LINE );
    }
    return result.toString();
  }

  /** Demonstrate output.  */
  public static void main (String... aArguments){
    final Throwable throwable = new IllegalArgumentException("Blah");
    System.out.println( getStackTrace(throwable) );
    System.out.println( getCustomStackTrace(throwable) );
  }
} 

Answer 5

沿着 Guava 的路线，Apache Commons Lang 在 org.apache.commons.lang.exception 中具有 ExceptionUtils.getFullStackTrace。 来自 StackOverflow 上的先前答案。

Answer 6

StackTraceElement[] stack = new Exception().getStackTrace();
String theTrace = "";
for(StackTraceElement line : stack)
{
   theTrace += line.toString();
}

Answer 7

使用 apache commons-lang3 库

import org.apache.commons.lang3.exception.ExceptionUtils;

//...

String[] ss = ExceptionUtils.getRootCauseStackTrace(e);
logger.error(StringUtils.join(ss, System.lineSeparator()));

Answer 8

call:  getStackTraceAsString(sqlEx)

public String getStackTraceAsString(Exception exc)  
{  
String stackTrace = "*** Error in getStackTraceAsString()";

ByteArrayOutputStream baos = new ByteArrayOutputStream();
PrintStream ps = new PrintStream( baos );
exc.printStackTrace(ps);
try {
    stackTrace = baos.toString( "UTF8" ); // charsetName e.g. ISO-8859-1
    } 
catch( UnsupportedEncodingException ex )
    {
    Logger.getLogger(sss.class.getName()).log(Level.SEVERE, null, ex);
    }
ps.close();
try {
    baos.close();
    } 
catch( IOException ex )
    {
    Logger.getLogger(sss.class.getName()).log(Level.SEVERE, null, ex);
    }
return stackTrace;
}