将整数转换为字节（对于 PySerial，使用 Python25）

发布于 2024-10-14 13:15:46 字数 727 浏览 3 评论 0原文

这看起来应该很简单，但我一直无法弄清楚...

我正在尝试使用 PySerial 与微控制器通信。我想发送一个索引位置，但是当我发送它时，PySerial 会发送该数字的 ASCII（所以当我发送 0 时，它会发送 48）。

我知道对于 Python26 及更高版本，我只需用内置的 bytes 函数将数字括起来，如下所示：

self.index = bytes([index])

但是，Python25 没有该函数。我找不到任何建议等效的文档。有人知道我应该做什么吗？

提前致谢！

编辑：抱歉，这是我的代码的简化版本...

class SecondaryImage():
    def __init__(self, index):
        self.index = index
    def sendIndex(self):
        serial.write(self.index)

for i in range(64):
    img = SecondaryImage(i)
    imgs.append(img)

然后我会单独调用 sendIndex() -

imgs[2].sendIndex()

原文

This seems like it should be simple, but I haven't been able to figure it out...

I'm trying to use PySerial to communicate with a microcontroller. I want to send an index location, but when I send it, it PySerial sends the ASCII of the number (so when I send a 0, it sends 48).

I know for Python26 and up, I would just enclose the number with the built-in bytes function like so:

self.index = bytes([index])

However, Python25 doesn't have that function. I can't find any documentation suggesting an equivalent. Does anybody know what I should do?

Thanks in advance!

EDIT: Sorry, here's a simplified version of my code...

class SecondaryImage():
    def __init__(self, index):
        self.index = index
    def sendIndex(self):
        serial.write(self.index)

for i in range(64):
    img = SecondaryImage(i)
    imgs.append(img)

And then I'd call sendIndex() seperately--