手势识别器和按钮操作

Question

我有一个看起来像这样的视图层次结构：

UIView (A)
UIView > UIImageView
UIView > UIView (B)
UIView > UIView (B) > Rounded Rect Button
UIView > UIView (B) > UIImageView
UIView > UIView (B) > UILabel

我已将手势识别器附加到我的 UIView (B)。我面临的问题是，我没有对 UIView (B) 内的圆角矩形按钮执行任何操作。 singleTap 手势识别器捕获/覆盖按钮的 Touch Up Inside 事件。

我怎样才能让它发挥作用？我认为响应者链层次结构将确保按钮触摸事件被优先考虑，并且它将被触发！我缺少什么？

这是一些相关代码：

#pragma mark -
#pragma mark View lifecycle (Gesture recognizer setup)

- (void)viewDidLoad {
    [super viewDidLoad];

    // double tap gesture recognizer
    UITapGestureRecognizer *dtapGestureRecognize = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doubleTapGestureRecognizer:)];
    dtapGestureRecognize.delegate = self;
    dtapGestureRecognize.numberOfTapsRequired = 2;
    [self.viewB addGestureRecognizer:dtapGestureRecognize];

    // single tap gesture recognizer
    UITapGestureRecognizer *tapGestureRecognize = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(singleTapGestureRecognizer:)];
    tapGestureRecognize.delegate = self;
    tapGestureRecognize.numberOfTapsRequired = 1;
    [tapGestureRecognize requireGestureRecognizerToFail:dtapGestureRecognize];
    [self.viewB addGestureRecognizer:tapGestureRecognize];

    // add gesture recodgnizer to the grid view to start the edit mode
    UILongPressGestureRecognizer *pahGestureRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressGestureRecognizerStateChanged:)];
    pahGestureRecognizer.delegate = self;
    pahGestureRecognizer.minimumPressDuration = 0.5;
    [self.viewB addGestureRecognizer:pahGestureRecognizer];

    [dtapGestureRecognize release];
    [tapGestureRecognize release];
    [pahGestureRecognizer release];
}

#pragma mark -
#pragma mark Button actions

- (IBAction)buttonTouchUpInside:(id)sender {
    NSLog(@"%s, %@", __FUNCTION__, sender);
}

#pragma mark -
#pragma mark Gesture recognizer actions


- (void)singleTapGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"%s", __FUNCTION__);
}

- (void)doubleTapGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"%s", __FUNCTION__);
}

- (void)longPressGestureRecognizerStateChanged:(UIGestureRecognizer *)gestureRecognizer {

    switch (gestureRecognizer.state) {

        case UIGestureRecognizerStateEnded: {
            NSLog(@"%s", __FUNCTION__);

            break;
        }
        default:
            break;
    }
}

Answer 1

在“shouldReceiveTouch”方法中，您应该添加一个条件，如果触摸位于按钮中，则返回 NO。

这是来自苹果 SimpleGestureRecognizers 示例。

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {

    // Disallow recognition of tap gestures in the segmented control.
    if ((touch.view == yourButton)) {//change it to your condition
        return NO;
    }
    return YES;
}

希望它会有所帮助

编辑

正如 Daniel 指出的，您必须遵守 UIGestureRecognizerDelegate 才能正常工作。

沙尼

Answer 2

我也遇到了同样的问题，然后我尝试了

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch{

    if ([touch.view isKindOfClass:[UIButton class]]) {      //change it to your condition
        return NO;
    }
    return YES;
}

它现在工作正常..............

Answer 3

一般来说，我们使用下面的委托方法来避免各种UIControls中的触摸：

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    if (([touch.view isKindOfClass:[UIControl class]])) {
         return NO;
    }
    return YES;
}

注意：不要对gestureRecognizerShouldBegin进行此检查（检查recognizer.view类类型），它不会起作用。

Answer 4

这是一个 Swift 3.0 版本：

extension UIViewController: UIGestureRecognizerDelegate {

public func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    if touch.view is UIButton {
        return false
    }
    return true
}

不要忘记：

让你的 Tapper 对象委托给 self（例如：tapper.delegate = self）

Answer 5

在我看来，最好的解决方案是使用下面的代码片段：

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    CGPoint touchLocation = [touch locationInView:self.view];
    return !CGRectContainsPoint(self.menuButton.frame, touchLocation);
}

Answer 6

这是一个 Swift 版本：

func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -> Bool {
    if (touch.view!.isKindOfClass(UIButton)) {
        return false
    }
    return true
}

不要忘记：

1. 让你的类符合 UIGestureRecognizerDelegate
2. 让你的 Tapper 对象委托给 self（例如：tapper.delegate = self）

Answer 7

对于委托内的 Swift 5，您只需添加：

return (touch.view is UIButton) ? false : true

Answer 8

Vivienne 答案的 Swift 版本：

func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    let location = touch.location(in: view)
    return !someView.frame.contains(location)
}

Answer 9

我的情况如下：

UIView (with tap gesture)
├-> UIView (named "textFieldView")
    ├-> UIControl
    ├-> UITextField
    ├-> UIView (over the textField, with a tap gesture)

╭──────────────────────────────╮
│ ╭──────────────────────────╮ │
│ │ ╭──╮  ┌╴╶╴╶╴╶╴╶╴╶╴╶╴╶╴╶┐ │ │
│ │ ╰──╯  └╴╶╴╶╴╶╴╶╴╶╴╶╴╶╴╶┘ │ │
│ ╰──────────────────────────╯ │
└──────────────────────────────┘

上部 UIView 上的 tapGesture 导致与 UIControl 目标发生冲突。如果目标是使用 touchDown 设置的（但未调用 touchUpInside），或者如果我将继承从 UIControl 更改为 < code>UIButton，同时保持事件 touchUpInside 上的目标设置。

我要做的就是解决这个问题：
上视图被设置为其点击手势的代表。
函数 funcgestureRecognizer(_gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool 的实现（在上层 UIView 中）如下所示：

func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    let touchLocationRelatedToTextFieldView = touch.location(in: textFieldView)
    return textFieldView.frame.contains(touchLocationRelatedToTextFieldView) == false
}

通过实现该委托函数，我现在可以将 UIControl 和目标设置保留在 touchUpInside 上！ :)